两次之间的 PHP 小时和分钟

Question

$time1 = "14:45";
$time2 = "15:55";
list($hours, $minutes) = explode(':', $time1);
$startTimestamp = mktime($hours, $minutes);

list($hours, $minutes) = explode(':', $time2);
$endTimestamp = mktime($hours, $minutes);

$seconds = $endTimestamp - $startTimestamp;
$minutes = ($seconds / 60) % 60;
$hours = round($seconds / (60 * 60));

echo "<b>$hours</b> hours and<b>$minutes</b> minutes</b>";

如果变量 time1 小于变量 time2，则此代码运行良好，但如果 time1 为“23:35”且 time2 为“01:40”，它将输出“-22 小时 -55 分钟”。

我该如何纠正这个问题，即使 time1 低于 time2 变量，它仍然会输出两个时间之间的小时和分钟

此代码将采用两次示例“14:45”和“16:33”并计算每次之间的小时数和分钟数，但如果“time1”低于"time2" (time1 和 time2 是变量)

http://codepad.org/QmFdN6RV

Answer 1

所以不知道你真正想要什么结果 - 可能有两种方式，所以我都做;）

你还必须使用地板而不是圆形。

第一个解决方案是，您根据同一天获得差异：

<?php
$time1 = "23:45";
$time2 = "01:44";
list($hours, $minutes) = explode(':', $time1);
$firstTimestamp = mktime($hours, $minutes);

list($hours, $minutes) = explode(':', $time2);
$secondTimestamp = mktime($hours, $minutes);

$firstTimestamp > $secondTimestamp?$seconds = $firstTimestamp - $secondTimestamp:$seconds = $secondTimestamp - $firstTimestamp;

$minutes = ($seconds / 60) % 60;
$hours = floor($seconds / (60 * 60));

echo "<b>$hours</b> hours and <b>$minutes</b> minutes</b>";
?>

输出将是：22 小时和 1 分钟

第二种方式是，结束时间（命名为 secondtime）是第二天 应该是这样的

<?php
$time1 = "23:45";
$time2 = "01:24";
list($hours, $minutes) = explode(':', $time1);
$firstTimestamp = mktime($hours, $minutes);

list($hours, $minutes) = explode(':', $time2);
$secondTimestamp = mktime($hours, $minutes);

$seconds =  $secondTimestamp - $firstTimestamp;

$seconds<0?$seconds+=24*60*60:"";

$minutes = ($seconds / 60) % 60;
$hours = floor($seconds / (60 * 60));


echo "<b>$hours</b> hours and <b>$minutes</b> minutes</b>";
?>

输出将是：1 小时和 39 分钟

到键盘的网址：http://codepad.org/7plRAhZJ

Answer 2

我就是这样做的，使用strtotime():

// If dates are not specified, strtotime() will assume both are from today
$time1 = "23:45";
$time2 = "01:24";

// Absolute value of time difference in seconds
$diff = abs(strtotime($time1) - strtotime($time2));

// Convert $diff to minutes
$tmins = $diff/60;

// Get hours
$hours = floor($tmins/60);

// Get minutes
$mins = $tmins%60;

See demo

这假设$time1 和$time2 来自同一天。如果不是，则需要指定。

$time1 = "today 23:45";
$time2 = "tomorrow 01:24";
// or
$time1 = "2014-7-3 23:45";
$time2 = "2014-7-4 01:24";
// or some other method of specifying the day.

See demo 2

Answer 3

如果秒数为负数，则添加 24 小时：

$time1 = "23:35";
$time2 = "1:40";  
list($hours, $minutes) = explode(':', $time1);
$startTimestamp = mktime($hours, $minutes);

list($hours, $minutes) = explode(':', $time2);
$endTimestamp = mktime($hours, $minutes);

$seconds = $endTimestamp - $startTimestamp;
if($seconds < 0) {
    $seconds+=60*60*24; 
}

$minutes = ($seconds / 60) % 60;
$hours = round($seconds / (60 * 60));

echo "<b>$hours</b> hours and<b>$minutes</b> minutes</b>";

Answer 4

你会这样做：

$time1 = "23:40";
$time2 = "01:40";
list($hours, $minutes) = explode(':', $time1);
$startTimestamp = mktime($hours, $minutes);

list($hours, $minutes) = explode(':', $time2);
$endTimestamp = mktime($hours, $minutes);

$seconds = abs($endTimestamp - $startTimestamp);
$diff = (24*60*60)-$seconds;
if ($diff < $seconds) {
    $seconds = $diff;
}

$minutes = ($seconds / 60) % 60; 
$hours = round($seconds / (60 * 60));

echo "<b>$hours</b> hours and<b>$minutes</b> minutes</b>"

请注意，这绝不会给您带来大于 12h 的差异。

例如，06:00 和 22:00 之间的差是 8 小时

Answer 5

你可以使用date_diff

$date1 = new DateTime();
$date2 = new DateTime();
$date1->setTimestamp($startTimestamp);
$date2->setTimestamp($endTimestamp);
$interval = date_diff($date1, $date2);
//or $interval = $date1->diff($date2)
echo $interval->format('%h hours and %m minutes');