我们如何在 PHP 中添加两个日期间隔

Question

我想添加两个日期间隔来计算以小时和分钟为单位的总持续时间，实际上我想执行如下所示的添加：

$a = new DateTime('14:25');
$b = new DateTime('17:30');
$interval1 = $a->diff($b);
echo "interval 1 : " . $interval1->format("%H:%I");
echo "<br />";

$c = new DateTime('08:00');
$d = new DateTime('13:00');
$interval2 = $c->diff($d);
echo "interval 2 : " . $interval2->format("%H:%I");
echo "<br />";

echo "Total interval : " . $interval1 + $interval2;

知道如何执行这种类型的间隔加法以在 PHP 中以总小时和分钟格式获得两个间隔的总和

Answer 1

PHP 没有运算符重载*，因此 + 带有对象使得 PHP 尝试首先将它们转换为字符串，但 DateInterval 不支持：

interval 1: 03:05
interval 2: 05:00
Total interval : 08:05

您需要创建一个新的DateTime 对象，然后使用add 函数添加间隔，最后显示与参考点的差异：

$e = new DateTime('00:00');
$f = clone $e;
$e->add($interval1);
$e->add($interval2);
echo "Total interval : ", $f->diff($e)->format("%H:%I"), "\n";

完整示例/(Demo)：

$a = new DateTime('14:25');
$b = new DateTime('17:30');
$interval1 = $a->diff($b);
echo "interval 1: ", $interval1->format("%H:%I"), "\n";

$c = new DateTime('08:00');
$d = new DateTime('13:00');
$interval2 = $c->diff($d);
echo "interval 2: ", $interval2->format("%H:%I"), "\n";

$e = new DateTime('00:00');
$f = clone $e;
$e->add($interval1);
$e->add($interval2);
echo "Total interval : ", $f->diff($e)->format("%H:%I"), "\n";

---

您可能还想考虑查看DateInterval 如何存储其值，然后从它扩展以进行您自己的计算。下面的例子（Demo）很粗略，它没有考虑the inverted thingy，它确实考虑了not (re)set $days to false，我还没有检查/测试the period specifier on creation的ISO规范，但我认为这足以说明这个想法：

class MyDateInterval extends DateInterval
{
    /**
     * @return MyDateInterval
     */
    public static function fromDateInterval(DateInterval $from)
    {
        return new MyDateInterval($from->format('P%yY%dDT%hH%iM%sS'));
    }
                                  
    public function add(DateInterval $interval)
    {
        foreach (str_split('ymdhis') as $prop)
        {
            $this->$prop += $interval->$prop;
        }
    }
}

$a = new DateTime('14:25');
$b = new DateTime('17:30');
$interval1 = $a->diff($b);
echo "interval 1: ", $interval1->format("%H:%I"), "\n";

$c = new DateTime('08:00');
$d = new DateTime('13:00');
$interval2 = $c->diff($d);
echo "interval 2: ", $interval2->format("%H:%I"), "\n";
                                  
$e = MyDateInterval::fromDateInterval($interval1);
$e->add($interval2);
echo "Total interval: ", $e->format("%H:%I"), "\n";

---

^* 如果你写一个 PHP 扩展，它实际上是可能的（至少在某种程度上）。

Answer 2

此函数允许您组合任意数量的 DateIntervals

/**
 * Combine a number of DateIntervals into 1 
 * @param DateInterval $...
 * @return DateInterval
 */
function addDateIntervals()
{
    $reference = new DateTimeImmutable;
    $endTime = clone $reference;

    foreach (func_get_args() as $dateInterval) {
        $endTime = $endTime->add($dateInterval);
    }

    return $reference->diff($endTime);
}

Answer 3

function compare_dateInterval($interval1, $operator ,$interval2){
    $interval1_str = $interval1->format("%Y%M%D%H%I%S");
    $interval2_str = $interval2->format("%Y%M%D%H%I%S");
    switch($operator){
        case "<":
            return $interval1 < $interval2;
        case ">":
            return $interval1 > $interval2;
        case "==" :
            return $interval1 == $interval2;
        default:
            return NULL;
    }
}
function add_dateInterval($interval1, $interval2){
    //variables
    $new_value= [];
    $carry_val = array(
                    's'=>['value'=>60,'carry_to'=>'i'],
                    'i'=>['value'=>60,'carry_to'=>'h'],
                    'h'=>['value'=>24,'carry_to'=>'d'],
                    'm'=>['value'=>12,'carry_to'=>'y']
                );

    //operator selection
    $operator = ($interval1->invert == $interval2->invert) ? '+' : '-';

    //Set Invert
    if($operator == '-'){
        $new_value['invert'] = compare_dateInterval($interval1,">",$interval2)?$interval1->invert:$interval2->invert;
    }else{
        $new_value['invert'] = $interval1->invert;
    }

    //Evaluate
    foreach( str_split("ymdhis") as $property){
        $expression = 'return '.$interval1->$property.' '.$operator.' '.$interval2->$property.';';
        $new_value[$property] = eval($expression);
        $new_value[$property] = ($new_value[$property] > 0) ? $new_value[$property] : -$new_value[$property];
        }

    //carry up
    foreach($carry_val as $property => $option){
        if($new_value[$property] >= $option['value']){
            //Modulus
            $new_value[$property] = $new_value[$property] % $option['value'];
            //carry over
            $new_value[$option['carry_to']]++;
        }
    }

    $nv = $new_value;
    $result = new DateInterval("P$nv[y]Y$nv[m]M$nv[d]DT$nv[h]H$nv[i]M$nv[s]S");
    $result->invert = $new_value['invert'];
    return $result;
}

$a = new DateTime('00:0');
$b = new DateTime('17:30');
$interval1 = $a->diff($b);
echo "interval 1: ", $interval1->format("%H:%I"), "<br>";

$c = new DateTime('08:01:00');
$d = new DateTime('13:30:33');
$interval2 = $c->diff($d);
echo "interval 2: ", $interval2->format("%H:%I"), "<br>";

$addition = add_dateInterval($interval1,$interval2);
echo "<pre>";
echo var_dump($addition);
echo "</pre>";

Answer 4

我也有同样的情况。我通过创建一个新的stdClass 来解决我的问题，该对象模拟DateInterval 对象，但它不是真正的DateInterval 对象。然后，我在对所需属性执行复合赋值操作（例如+=）时遍历每个真实的DateInterval。见下文：

$dateTimeA = new DateTime('-10 day');
$dateTimeB = new DateTime('-8 day');
$dateTimeC = new DateTime('-6 day');
$dateTimeD = new DateTime('-4 day');

$intervalA = date_diff($dateTimeA, $dateTimeB);
$intervalB = date_diff($dateTimeC, $dateTimeD);

$intervalC = new StdClass; // $intervalC is an emulation of DateInterval 
$intervalC->days = 0;

foreach([$intervalA, $intervalB] as $interval) {
    $intervalC->days += (int)$interval->format('%d');
}


var_dump($intervalC);
/*
object(stdClass)[7]
  public 'days' => int 4
*/