如何将秒数转换为人类可读的日期

Question

我正在尝试将表示自 1970 年 1 月 1 日以来秒数的任意整数值转换为人类可读的日期。

这是我得到的最接近的日期，但我一直得到当前日期。如何获取不是当前日期的struct tm？

#include <iostream> 
#include <string>
#include <time.h>

using namespace std;

int main() {
  struct tm * timeStruct;
  time_t myTime = 946684800; //s from 1970 to 2000
  int timeStamp = time(&myTime); //I thought this would set the date to the values of myTime, it just sets it to now
  timeStruct = localtime(&myTime);
  cout << timeStamp;
  cout << "\n";
  cout << asctime(timeStruct); //This should read Jan 1, 2000, instead it keeps giving me the current time
  cout << "\n";
  system("pause");
  return 0;
}

Answer 1

time(&myTime) 将 myTime 的值设置为当前时间（这显然是意料之中的）。

解决方案：

#include <iostream> 
#include <string>
#include <time.h>

using namespace std;

int main() {
  struct tm * timeStruct;
  time_t myTime = 946684800; //s from 1970 to 2000

  int timeStamp = myTime;
  timeStruct = localtime(&myTime);

  cout << timeStamp;

  cout << "\n";

  cout << asctime(timeStruct);

  cout << "\n";

  system("pause");

  return 0;
}