【发布时间】:2014-10-20 08:29:59
【问题描述】:
我是一名新手,正在尝试使用 Raspberry Pi 学习 Python。我一直在编写一些代码来尝试为板载 piFace 添加一个简单的模拟器。
它存在一些问题,我正在努力解决这些问题。
我的代码会打开一个窗口并显示一个切换按钮,该按钮可以打开/关闭 LED 图像。我还添加了一个打开子窗口的按钮。子窗口有两个按钮。一个是打开/关闭 LED 图像的开关按钮,另一个是退出按钮。
我的问题是,如果我使用“退出”按钮,当 LED 处于“打开”状态时,子窗口会关闭,这是应该的。但是,如果我重新打开子窗口并使用切换按钮打开 LED,则没有任何反应。如果我再次按下切换按钮,LED 就会亮起。
我有点理解问题所在。因为当 LED 处于“打开”状态时我关闭了子窗口,所以切换按钮状态仍处于打开状态。而且,当我重新打开窗口并单击切换按钮时,我只是将切换按钮状态设置为 OFF。
我不知道如何解决这个问题。我是否应该以不同且可能正确的方式关闭窗口?每次打开子窗口时,我是否应该查看一种预设拨动开关状态的方法?我应该尝试完全不同的东西吗?我应该完全停止吗? :-)
我希望这是有道理的。
感谢您的帮助。
这是我的代码....
# Idle 10_01_2014_GUI label image toggle
from time import sleep
from Tkinter import *
import Tkinter as tk
import threading
class App:
def __init__(self, master):
self.master=master
frame = Frame(master)
frame.pack()
Label(frame, text='Turn LED ON').grid(row=0, column=0)
Label(frame, text='Turn LED OFF').grid(row=0, column=1)
self.button0 = Button(frame, text='LED 0 OFF', command=self.convert0)
self.button0.grid(row=2, column=0)
self.LED0 = Label(frame, image=logo2)
self.LED0.grid(row=2, column=1)
self.buttonnewwindow = Button(frame, text='Knight Rider TEST', command=self.new_window)
self.buttonnewwindow.grid(row=10, column=0)
self.button8 = Button(frame, text='Exit', command=quit)
self.button8.grid(row=11, column=0)
def convert0(self, tog=[0]):
tog[0] = not tog[0]
if tog[0]:
print('LED 0 ON')
self.button0.config(text='LED 0 ON')
self.LED0.config(image = logo)
self.LED0.grid(row=2, column=1)
else:
print('LED 0 OFF')
self.button0.config(text='LED 0 OFF')
self.LED0.config(image = logo2)
self.LED0.grid(row=2, column=1)
def new_window(self):
print('New Window')
self.newWindow = tk.Toplevel(self.master)
self.app = App2(self.newWindow)
self.newWindow.grab_set() # I added this line to stop opening multiple new windows
class App2:
def __init__(self, master):
self.signal = False
print('self.signal', self.signal)
self.master=master # I added this line to make the exit button work
frame = Frame(master)
frame.pack()
Label(frame, text='Turn LED ON').grid(row=0, column=0)
Label(frame, text='Turn LED OFF').grid(row=0, column=1)
self.button0 = Button(frame, text='Knight Rider OFF', command=self.convert0)
self.button0.grid(row=2, column=0)
self.LED0 = Label(frame, image=logo2)
self.LED0.grid(row=2, column=1)
self.button9 = Button(frame, text='Exit', command=self.close_window)
self.button9.grid(row=3, column=0)
def convert0(self, tog=[0]):
tog[0] = not tog[0]
if tog[0]:
print('Knight Rider ON')
self.button0.config(text='Knight Rider ON')
self.signal = True
print('self.signal', self.signal)
print('tog[0]', tog[0])
self.LED0.config(image = logo)
else:
print('Knight Rider OFF')
self.button0.config(text='Knight Rider OFF')
self.signal = False
print('self.signal', self.signal)
print('tog[0]', tog[0])
self.LED0.config(image = logo2)
def close_window(self):
print('Knight Rider OFF')
print('self.signal', self.signal)
self.button0.config(text='Knight Rider OFF')
self.LED0.config(image = logo2)
self.signal = False
print('self.signal', self.signal)
sleep(.5)
print('Close Child window')
self.master.destroy() # I added this line to make the exit button work
root = Tk()
logo2 = PhotoImage(file="c:\\Users\\joebloggs\\Downloads\\led-off.gif")
logo = PhotoImage(file="c:\\Users\\joebloggs\\Downloads\\led-on.gif")
root.wm_title('LED on & off program')
app = App(root)
root.mainloop()
【问题讨论】:
标签: python tkinter state exit togglebutton