TSQL datediff 仅营业时间

Question

在一个视图中，这两个日期来自一个表：

2014-12-17 14:01:03.523 - 2014-12-20 09:59:28.783

假设我可以计算一天中从早上 8 点到下午 5 点的小时数，我需要知道日期差异（以小时为单位）。

当然不能包括周六和周日。

我尝试在选择中使用此代码，但我只得到了几天的差异，不包括周六和周日。

(DATEDIFF(HOUR, convert(datetime,t.EXT_DATAINS-2), convert(datetime,b.EXT_DATAINS-2)) + 1) 
  -(DATEDIFF(wk, convert(datetime,t.EXT_DATAINS-2), convert(datetime,b.EXT_DATAINS-2)) * 2)
  -(CASE WHEN DATENAME(dw, convert(datetime,t.EXT_DATAINS-2)) = 'Sunday' THEN 1 ELSE 0 END)
  -(CASE WHEN DATENAME(dw, convert(datetime,b.EXT_DATAINS-2)) = 'Saturday' THEN 1 ELSE 0 END) differenza

例子：

2014-12-17 : 3hrs
2014-12-18 : 8hrs
2014-12-19 : 8hrs
2014-12-20 : 2hrs 
Tot        : 21hrs

Answer 1

使用Recursive CTE 获取所有带日期的小时。

方法 1：获取 FromDate 和 ToDate 之间的所有日期

DECLARE @FROMDATE DATETIME='2014-12-17 14:01:03.523'
DECLARE @TODATE DATETIME='2014-12-20 09:59:28.783'

;WITH CTE AS
(
   SELECT @FROMDATE FROMDATE
   UNION ALL
   SELECT DATEADD(HH,1,FROMDATE)
   FROM CTE
   WHERE FROMDATE<@TODATE 
)
SELECT ISNULL(CAST(CAST(FROMDATE AS DATE)AS VARCHAR(12)),'Tot')FROMDATE,
CAST(COUNT(FROMDATE)AS VARCHAR(4))+'hrs' [HOURS] 
FROM CTE
WHERE DATEPART(HH,FROMDATE) BETWEEN 9 AND 16
AND DATENAME(DW,FROMDATE)<>'SATURDAY' AND DATENAME(DW,FROMDATE)<>'SUNDAY'
GROUP BY CAST(FROMDATE AS DATE)
WITH ROLLUP

• SQL FIDDLE

方法 2：获取 FromDate 和 ToDate 之间缺失的日期，其中 8 硬编码为 Hrs

这种方法将更易于实施 - 性能调整

DECLARE @FROMDATE DATETIME='2014-12-17 14:01:03.523'
DECLARE @TODATE DATETIME='2014-12-20 09:59:28.783'

;WITH CTE AS
(
   -- Get missing dates between FromDate and ToDate
   SELECT  DATEADD(DAY,1,@FROMDATE) FROMDATE,8 HRS
   UNION ALL
   SELECT DATEADD(DAY,1,FROMDATE),8
   FROM CTE
   WHERE FROMDATE < DATEADD(DAY,-1,@TODATE) 
)
,CTE2 AS
(
   -- Gets the Hours for FromDate
   SELECT CAST(@FROMDATE AS DATE) DATES, CAST(CAST(DATEDIFF
   (
      MINUTE,@FROMDATE,CAST(CAST(CAST(@FROMDATE AS DATE) AS VARCHAR(12))+' 17:00:00' AS DATETIME)
   )AS NUMERIC(18,2))/60 AS DECIMAL(18,0)) HRS
   WHERE DATENAME(DW,@FROMDATE)<>'SATURDAY' AND DATENAME(DW,@FROMDATE)<>'SUNDAY'

   UNION ALL

   -- Select Hours in between dates
   SELECT CAST(FROMDATE AS DATE) NEWDATE,HRS
   FROM CTE
   WHERE DATENAME(DW,FROMDATE)<>'SATURDAY' AND DATENAME(DW,FROMDATE)<>'SUNDAY'

   UNION ALL

   -- Select Hours for ToDate
   SELECT CAST(@TODATE AS DATE), CAST(CAST(DATEDIFF
   (
      MINUTE,CAST(CAST(CAST(@TODATE AS DATE) AS VARCHAR(12))+' 08:00:00' AS DATETIME),@TODATE
   )AS NUMERIC(18,2))/60 AS DECIMAL(18,0))
   WHERE DATENAME(DW,@TODATE)<>'SATURDAY' AND DATENAME(DW,@TODATE)<>'SUNDAY'
)
-- Use ROLLUP to find the sum of Hours and show it in last row
SELECT ISNULL(CAST(DATES AS VARCHAR(20)),'Tot')DATES,
CAST(SUM(HRS)AS VARCHAR(4))+'hrs' HRS
FROM CTE2
GROUP BY DATES
WITH ROLLUP

• SQL FIDDLE

Answer 2

@marco burrometo

创建一个静态表，该表将具有所有日历功能，例如假期功能，周六和周日是假期。对你有很大帮助。