iOS：如何创建一个独立的框架

Question

我正在创建一个小 SDK，我想发布一个 Foo.framework。 我所做的如下：

1- 创建项目框架。

2- 添加我的代码。

3- 添加聚合器。

在聚合器构建阶段我添加了这个运行脚本

#!/bin/sh
UNIVERSAL_OUTPUTFOLDER=${BUILD_DIR}/${CONFIGURATION}-universal
//make sure the output directory exists
mkdir -p "${UNIVERSAL_OUTPUTFOLDER}"
//Step 1. Build Device and Simulator versions
xcodebuild -target "${PROJECT_NAME}" ONLY_ACTIVE_ARCH=NO -configuration ${CONFIGURATION} -sdk iphoneos  BUILD_DIR="${BUILD_DIR}" BUILD_ROOT="${BUILD_ROOT}" clean build
xcodebuild -target "${PROJECT_NAME}" -configuration ${CONFIGURATION} -sdk iphonesimulator ONLY_ACTIVE_ARCH=NO BUILD_DIR="${BUILD_DIR}" BUILD_ROOT="${BUILD_ROOT}" clean build
//Step 2. Copy the framework structure (from iphoneos build) to the universal folder
cp -R "${BUILD_DIR}/${CONFIGURATION}-iphoneos/${PROJECT_NAME}.framework" "${UNIVERSAL_OUTPUTFOLDER}/"
//Step 3. Create universal binary file using lipo and place the combined executable in the copied framework directory
lipo -create -output "${UNIVERSAL_OUTPUTFOLDER}/${PROJECT_NAME}.framework/${PROJECT_NAME}" "${BUILD_DIR}/${CONFIGURATION}-iphonesimulator/${PROJECT_NAME}.framework/${PROJECT_NAME}" "${BUILD_DIR}/${CONFIGURATION}-iphoneos/${PROJECT_NAME}.framework/${PROJECT_NAME}"
//Step 4. Convenience step to copy the framework to the project's directory
cp -R "${UNIVERSAL_OUTPUTFOLDER}/${PROJECT_NAME}.framework" "${PROJECT_DIR}"
//Step 5. Convenience step to open the project's directory in Finder
open "${PROJECT_DIR}"

然后我构建聚合器并获取 Foo.framwork 我的问题是，为了能够在另一个应用程序中使用该框架，我应该：

第 1 步 - 将框架拖放到我的项目中。

第 2 步 - 并将其添加到嵌入式二进制文件中。

如果我不执行第 2 步，我会收到此错误

dyld: Library not loaded: @rpath/Foo.framework/Foo
Referenced from: /private/var/mobile/Containers/Bundle/Application/00A2E4FD-23F4-43E8-AA85-505785A4FF16/foo.app/foo
Reason: image not found

如果我只想通过将框架拖到我的项目中来使用框架，我该怎么办 （换句话说，仅将其添加到 Link Binary with Library）以使其易于集成。 提前致谢。

Answer 1

对于所有面临此类问题的人来说，解决方案就在这里。 只需按照这些说明构建框架

https://github.com/jverkoey/iOS-Framework#walkthrough