导入脚本的问题

Question

您好，我一直在编写这个简单的脚本，但遇到了一些相当烦人的问题，我无法用 def 修复自己。和导入功能它只是行不通。这是主要脚本

import time         # This part import the time module
import script2      # This part imports the second script

def main():
    print("This program is a calaulater have fun using it")
    name = input("What is your name? ")
    print("Hello",name)
    q1 = input("Would you like to some maths today? ")

if q1 == "yes":
    script2 test()

if q1 == "no":
    print("That is fine",name,"Hope to see you soon bye")
    time.sleep(2)



if __name__ == '__main__':
    try:
        main()
    except Exception as e:
        time.sleep(10)      

然后第二个脚本被称为 script2 这里也是那个脚本 进口时间

def test():
    print("You would like to do some maths i hear.")
    print("you have some truely wonderfull option please chooice form the list below.")

这是我目前的脚本，但它不起作用，请帮助我。

Answer 1

首先，您的缩进似乎不正确。正如zvone所说。其次，您应该使用 script2.test() 而不是 script2 test()。一个功能代码是

import time         # This part import the time module
import script2      # This part imports the second script

def main():
    print("This program is a calaulater have fun using it")
    name = input("What is your name? ")
    print("Hello",name)
    q1 = input("Would you like to some maths today? ")

    if q1 == "yes":
        script2.test()

    if q1 == "no":
        print("That is fine",name,"Hope to see you soon bye")
        time.sleep(2)



if __name__ == '__main__':
    try:
        main()
    except Exception as e:
        time.sleep(10) 

Answer 2

这是一个错误：

def main():
    #...
    q1 = input("Would you like to some maths today? ")

if q1 == "yes":
    # ...

首先，main() 中的q1 和外部的q1 不是同一个变量。

其次，if q1 == "yes": 在 q1 = input(...) 之前执行，因为尚未调用 main()。

解决方案是从 main 返回 q1 值，然后才使用它：

def main():
    # ...
    return q1

if __name__ == '__main__':
    # ...
    result_from_main = main()    
    if result_from_main == "yes":
       # ...

当然，现在所有的名字都乱七八糟了，但那是另一个问题……