如何在 CoffeeScript 中编译匿名函数

Question

我正在创建 Backbone 插件，并假设我有如下 CoffeeScript 代码。

((root, factory) ->
  if typeof exports is "object" and typeof require is "function"
    # CommonJS
    module.exports = factory(require("backbone"))
  else if typeof define is "function" and define.amd
    # AMD
    define [
      "backbone"
    ], (Backbone) ->
      factory Backbone or root.Backbone
  else
    # Browser globals
    factory Backbone
) @, (Backbone) ->
  console.log Backbone # here will be main code.

然后我编译，结果是：

(function() {
  (function(root, factory) {
    if (typeof exports === "object" && typeof require === "function") {
      return module.exports = factory(require("backbone"));
    } else if (typeof define === "function" && define.amd) {
      return define(["backbone"], function(Backbone) {
        return factory(Backbone || root.Backbone);
      }); 
    } else {
      return factory(Backbone);
    }   
  })(this, function(Backbone) {
    return console.log(Backbone);
  }); 

}).call(this);

但是我想作为 2 个 CoffeeScript 文件（或任意数量的文件）进行潜水，然后通过 grunt-contrib-coffee 将它们连接起来，但编译后的 JS 应该是相同的结果。是否可以？你有什么想法吗？

a.coffee:

((root, factory) ->
  if typeof exports is "object" and typeof require is "function"
    # CommonJS
    module.exports = factory(require("backbone"))
  else if typeof define is "function" and define.amd
    # AMD
    define [
      "backbone"
    ], (Backbone) ->
      factory Backbone or root.Backbone
  else
    # Browser globals
    factory Backbone
) @, (Backbone) ->

b.coffee:

console.log Backbone

更新

按照 Kursion 的想法，我以某种方式实现了我想做的事情，虽然这很棘手；P

grunt indent -> grunt concat -> grunt coffee

  grunt.initConfig
    indent:
      scripts:
        src: ['src/main.coffee']
        dest: 'tmp/'
        options:
          style: 'space'
          size: 2
          change: 1

    concat:
      sources:
        options:
          separator: ''
        src: [
          'src/entry.coffee'
          'tmp/main.coffee'
        ]   
        dest: 'tmp/example.coffee'

    coffee:
      compile:
        files:
          'lib/example.js': 'tmp/example.coffee'

Answer 1

由于与 CoffeeScript 相关的缩进问题，这会很困难。

您可以做的是连接两个文件的脚本，但您需要尊重第二个文件中的缩进。

连接之后，您可以编译 CoffeeScript 源代码。

a.coffee

((root, factory) ->
  if typeof exports is "object" and typeof require is "function"
    # CommonJS
    module.exports = factory(require("backbone"))
  else if typeof define is "function" and define.amd
    # AMD
    define [
      "backbone"
    ], (Backbone) ->
      factory Backbone or root.Backbone
  else
    # Browser globals
    factory Backbone
) @, (Backbone) ->

b.coffee

    console.log Backbone # With indentation

---

两个文件的连接以便具有： glued.coffee

((root, factory) ->
  if typeof exports is "object" and typeof require is "function"
    # CommonJS
    module.exports = factory(require("backbone"))
  else if typeof define is "function" and define.amd
    # AMD
    define [
      "backbone"
    ], (Backbone) ->
      factory Backbone or root.Backbone
  else
    # Browser globals
    factory Backbone
) @, (Backbone) ->
    console.log Backbone # With indentation

然后编译：coffee --compile glued.coffee