按获胜次数排序排行榜答案

【问题标题】：Ordering a leader board numerically by wins按获胜次数排序排行榜
【发布时间】：2017-03-23 17:29:16
【问题描述】：

我的文本文件布局如下：名字、姓氏、胜负

杰克，霍弗隆，5,6

zack,macker,0,11

alex,hof,11,0

dex,gerred,2,9

cassy,comp,1,10

import csv
cho_two=int(input('gg:'))

class_a = open("prac2.txt")
csv_a = csv.reader(class_a)
a_list = []
for row in csv_a:
    row[0] = int(row[2])
    row[1] = int(row[2])
    row[2] = int(row[2])
    row[3] = int(row[2])
    a_list.append(row[0:3])
if cho_two == 1:
    numerical = [[x[0]] for x in a_list]
    print("\nCLASS A\nEach students highest by numerical order \n")
    for alpha_order in sorted(numerical, reverse=True):
        #csv_a.append(alpha_order)
        print(alpha_order)

class_a.close()

我正在尝试根据玩家获得的胜利次数来排序排行榜，并过滤掉没有获得单次胜利的玩家，我已经得到了排序胜利的结果，但我不知道如何将玩家信息附加到正确的中奖金额。

【问题讨论】：

标签： python python-3.x

【解决方案1】：

首先，我将通过将数据读入字典来创建一个名称 -> 胜负映射。

>>> with open('prac2.txt') as f:
...     stats = {}
...     for line in f:
...         first_name, last_name, wins, losses = line.split(',')
...         name = '{} {}'.format(first_name, last_name)
...         stats[name] = {'wins': int(wins), 'losses': int(losses)}
... 
>>> stats
{'zack macker': {'wins': 0, 'losses': 11}, 'jack hofferon': {'wins': 5, 'losses': 6}, 'dex gerred': {'wins': 2, 'losses': 9}, 'alex hof': {'wins': 11, 'losses': 0}, 'cassy comp': {'wins': 1, 'losses': 10}}

之后，遍历字典中按获胜次数排序的项目，如果玩家至少获胜一次，则打印出相关信息。下面是它的样子：

>>> sorted_items = sorted(stats.items(), key=lambda x: x[1]['wins'], reverse=True)
>>> for name, info in sorted_items:
...     wins = info['wins']
...     if wins > 0:
...         print('{} {}'.format(name, wins))
... 
alex hof 11
jack hofferon 5
dex gerred 2
cassy comp 1

【讨论】：

【解决方案2】：

以下代码使用pythonOrderedDict

import csv
from collections import OrderedDict

a_dict= {}
with open('prac2.txt', 'rb') as csvfile: # User with open so no need to worry about forget closing the file.
    csv_data = csv.reader(csvfile)
    for row in csv_data:
        # dictionary key is first name, value is number of wins
        # You can combine fn and sn together as key
        a_dict[row[0]] = int(row[2])
print "Unsorted"
for k, v in a_dict.items():
     print "%s: %s" % (k, v)
# Now sort by value in reverse order
d_sorted_by_value = OrderedDict(sorted(a_dict.items(), key=lambda x: x[1],reverse=True))

print "Sorted"
for k, v in d_sorted_by_value.items():
     print "%s: %s" % (k, v)

输出：

Unsorted
dex: 2
cassy: 1
alex: 11
jack: 5
zack: 0
Sorted
alex: 11
jack: 5
dex: 2
cassy: 1
zack: 0

【讨论】：

【解决方案3】：

如果你对数据科学方法一无所知，我推荐 pandas

import pandas as pd

leaderboard = pd.read_csv('leaders.txt', header=None)
#filter those who don't have any wins (0 in third column)
leaderboard = leaderboard[leaderboard[2] > 0]
#sort by third column
leaderboard.sort(2, ascending = False)

如果你想保存 csv，你只需 leaderboard.to_csv('ordered.txt', header=False)

【讨论】：