【发布时间】:2013-01-03 21:56:35
【问题描述】:
这是我的代码(为了代码的可读性,故意省略了错误检查):
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <gcrypt.h>
#define GCRYPT_VERSION "1.5.0"
#define GCRY_CIPHER GCRY_CIPHER_AES128
int main(void){
if(!gcry_check_version(GCRYPT_VERSION)){
fputs("libgcrypt version mismatch\n", stderr);
exit(2);
}
gcry_control(GCRYCTL_SUSPEND_SECMEM_WARN);
gcry_control(GCRYCTL_INIT_SECMEM, 16384, 0);
gcry_control(GCRYCTL_RESUME_SECMEM_WARN);
gcry_control (GCRYCTL_INITIALIZATION_FINISHED, 0);
int algo = -1;
size_t i;
const char *name = "aes128";
char plain_text[16] = {0x80};
char key[16] = {0};
char iniVector[16] = {0};
size_t txtLenght = strlen(plain_text);
char *encBuffer = malloc(txtLenght);
gcry_cipher_hd_t hd;
algo = gcry_cipher_map_name(name);
size_t blkLength = gcry_cipher_get_algo_blklen(GCRY_CIPHER);
size_t keyLength = gcry_cipher_get_algo_keylen(GCRY_CIPHER);
gcry_cipher_open(&hd, algo, GCRY_CIPHER_MODE_CBC, 0);
gcry_cipher_setkey(hd, key, keyLength);
gcry_cipher_setiv(hd, iniVector, blkLength);
gcry_cipher_encrypt(hd, encBuffer, txtLenght, plain_text, txtLenght);
printf("encBuffer = ");
for(i = 0; i < txtLenght; i++){
printf("%02x", (unsigned char) encBuffer[i]);
}
printf("\n");
gcry_cipher_close(hd);
free(encBuffer);
return 0;
}
预期结果:
KEY = 00000000000000000000000000000000
IV = 00000000000000000000000000000000
明文 = 80000000000000000000000000000000
密文 = 3ad78e726c1ec02b7ebfe92b23d9ec34
我的结果:
KEY = 00000000000000000000000000000000
IV = 00000000000000000000000000000000
明文 = 80000000000000000000000000000000
密文 = 42
为什么我得到这个输出?我做错了什么?
【问题讨论】:
-
您确定要包含结尾的空字符:
size_t txtLenght = strlen(plain_text)+1;`? -
天哪!你是对的!我已经更新了我的代码!
-
现在您确定您的纯文本、密钥和 iv 必须是 ascii 而不是十六进制?
-
我想过这个,但我不知道如何声明“十六进制数据类型”...
-
只需使用
char *plain_text = "\x80\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00"等等。