如何使用 arrayList 来存储用户输入的客户详细信息？

Question

1. try {
   Customer cst[] = {new Customer(), new Customer(),new Customer(),new Customer()};
   BufferedWriter bw = new BufferedWriter(new FileWriter("file.txt"));
   for (Customer a : cst) {
       bw.write(a+ " ");
           for (int i=0;i<cst.length;i++){
                System.out.println("Enter Customer Name : ");
                   cst[i] = new Customer();
                   cst[i].name = cst.nextLine();
                   cst[i].custID = 100 + (i+1);
                   System.out.println("Customer ID Generated is:"+cst[i].custID);
   
                }        
                   }
                  bw.close();
               } catch (Exception e) {
                   System.out.println("error: file not created");
               }  
       try {
                    BufferedReader br = new BufferedReader(new FileReader("file.txt"));
                    String s = "";
                    String msg = "";
                    while ((s = br.readLine()) != null) {
                       msg += s + " \n";
   
                   }
                    br.close();
                    System.out.println(msg);
   
               } catch (FileNotFoundException ex) {
                    System.out.println("Error: %s\n");
               }
   
               InputStreamReader isr = new InputStreamReader(System.in);
               BufferedReader br = new BufferedReader(isr);
            }
   

   好的。所以我认为这里的问题是“如何重写这段代码以使用 ArrayList 而不是静态数组？”但由于我实际上不是想知道的人，所以我会让他们确认或否认。

Answer 1

您使用s = br.readLine()，但在不创建新行的情况下存储它们。而不是bw.write(a+ " "); 尝试bw.write(a + "\n");