【发布时间】:2021-02-01 09:29:45
【问题描述】:
spyne库可以创建wsdlserver,wsdl示例代码:
from spyne.application import Application
from spyne.decorator import rpc
from spyne import ServiceBase, String
from spyne.protocol.soap import Soap11
from spyne.server.wsgi import WsgiApplication
from wsgiref.simple_server import make_server
class Test(ServiceBase):
@rpc(String, _returns=String)
def get_data(self, post_data):
return process_xml_data(post_data)
app = Application([Test], 'http://schemas.xmlsoap.org/soap/envelope',
in_protocol=Soap11(validator='lxml'), out_protocol=Soap11())
wsgi_app = WsgiApplication(app)
if __name__ == '__main__':
server = make_server('0.0.0.0', 8080, wsgi_app)
server.serve_forever()
所以我想知道有没有办法在flask 中创建wsdlservice?flask-spyne 根本不支持python3,它已经生命终结。
【问题讨论】:
-
我可能找到了解决方案:link
标签: python-3.x flask soap spyne