Group By后如何获得总数[重复]答案

【问题标题】：How to get total after Group By [duplicate]Group By后如何获得总数[重复]
【发布时间】：2018-11-16 04:15:51
【问题描述】：

SELECT COUNT(*) AS customer, t.state
  FROM tbl_parcel_item t
 WHERE t.courier_name='Tnt'
   AND t.date = '2018-03-12'
   AND t.ship_status NOT IN (0,1,9,10)
 GROUP BY t.state`

根据上面的 sql，结果将是： enter image description here 如何使其获得上述结果的总和，例如： enter image description here

【问题讨论】：

使用 sum(customer) 作为总数

标签： mysql sql phpmyadmin

【解决方案1】：

使用with rollup:

SELECT COUNT(*) AS customer, t.state`
FROM tbl_parcel_item t
WHERE t.courier_name = 'Tnt' AND
      t.date = '2018-03-12' AND
      t.ship_status NOT IN (0, 1, 9, 10)
GROUP BY t.state WITH ROLLUP;

【讨论】：

【解决方案2】：

全部使用联合：

`SELECT COUNT(*) AS customer, t.state`
`FROM tbl_parcel_item t`
`WHERE t.courier_name='Tnt'`
`AND t.date = '2018-03-12'`
`AND t.ship_status NOT IN (0,1,9,10)`
`GROUP BY t.state`
`UNION ALL`
`SELECT COUNT(*) AS customer, 'Total' as state`
`FROM tbl_parcel_item t`
`WHERE t.courier_name='Tnt'`
`AND t.date = '2018-03-12'`
`AND t.ship_status NOT IN (0,1,9,10)`

【讨论】：

【解决方案3】：

使用ROLLUP:

SELECT
    COALESCE(t.state, 'TOTAL') AS state,
    COUNT(*) AS customer
FROM tbl_parcel_item t
WHERE
    t.courier_name = 'Tnt' AND
    t.date = '2018-03-12'  AND
    t.ship_status NOT IN (0,1,9,10)
GROUP BY t.state WITH ROLLUP;

【讨论】：

【解决方案4】：

01) WITH ROLLUP 如其他答案中所述

02) 使用联合查询

  SELECT  t.state, COUNT(*) AS customer FROM tbl_parcel_item t WHERE t.courier_name='Tnt' AND t.date = '2018-03-12' AND t.ship_status NOT IN (0,1,9,10) GROUP BY t.state
  UNION 
  SELECT  'Total', COUNT(*) AS customer FROM tbl_parcel_item t WHERE t.courier_name='Tnt' AND t.date = '2018-03-12' AND t.ship_status NOT IN (0,1,9,10)

【讨论】：