在嵌套对象内排序答案

【问题标题】：Sorting inside nested object在嵌套对象内排序
【发布时间】：2020-04-11 23:57:57
【问题描述】：

我是 JS 初学者，正在尝试根据 SUFFIX 的键值对按升序对嵌套对象（即 PARTS）进行排序，如下所示：

Object: {
ID: 65,
MAIN: {ID: "GR", VALUE: 45},
PARTS:{
       0:{CODE: "GR3", PREFIX: "GR", SUFFIX: 3, YEAR: 3},
       1:{CODE: "GR4", PREFIX: "GR", SUFFIX: 4, YEAR: 2},
       2:{CODE: "GR1", PREFIX: "GR", SUFFIX: 1, YEAR: 5},
       3:{CODE: "GR2", PREFIX: "GR", SUFFIX: 2, YEAR: 4}
}
}

预期输出：

Object: {
ID: 65,
MAIN: {ID: "GR", VALUE: 45},
PARTS:{
       0:{CODE: "GR1", PREFIX: "GR", SUFFIX: 1, YEAR: 5},
       1:{CODE: "GR2", PREFIX: "GR", SUFFIX: 2, YEAR: 4},
       2:{CODE: "GR3", PREFIX: "GR", SUFFIX: 3, YEAR: 3},
       3:{CODE: "GR4", PREFIX: "GR", SUFFIX: 4, YEAR: 2}
}
}

任何建议如何获得所需的输出。

【问题讨论】：

拥有一个带有0...n 数字键的对象没有多大意义。为什么不使用数组？此外，即使在排序之后，CODE: 键看起来也是相同的。你能澄清一下吗？最后，我建议尝试一下并分享您的代码尝试。谢谢。

标签： javascript sorting object

【解决方案1】：

您可以使用values 获取PARTS 并排序，然后使用assign 将数组转换为对象。

let obj = {
ID: 65,
MAIN: {ID: "GR", VALUE: 45},
PARTS:{
       0:{CODE: "GR3", PREFIX: "GR", SUFFIX: 3, YEAR: 3},
       1:{CODE: "GR4", PREFIX: "GR", SUFFIX: 4, YEAR: 2},
       2:{CODE: "GR1", PREFIX: "GR", SUFFIX: 1, YEAR: 5},
       3:{CODE: "GR2", PREFIX: "GR", SUFFIX: 2, YEAR: 4}
}
}

let res = Object.values(obj.PARTS).sort((a,b) => a.SUFFIX - b.SUFFIX);

obj.PARTS = Object.assign({}, res);

console.log(obj)

let obj = {
ID: 65,
MAIN: {ID: "GR", VALUE: 45},
PARTS:{
       0:{CODE: "GR3", PREFIX: "GR", SUFFIX: 3, YEAR: 3},
       1:{CODE: "GR4", PREFIX: "GR", SUFFIX: 4, YEAR: 2},
       2:{CODE: "GR1", PREFIX: "GR", SUFFIX: 1, YEAR: 5},
       3:{CODE: "GR2", PREFIX: "GR", SUFFIX: 2, YEAR: 4}
}
}

let res = Object.values(obj.PARTS).sort((a,b) => a.SUFFIX - b.SUFFIX);

obj.PARTS = Object.assign({}, res);

console.log(obj)

【讨论】：

【解决方案2】：

var obj = {
ID: 65,
MAIN: {ID: "GR", VALUE: 45},
PARTS:{
       0:{CODE: "GR3", PREFIX: "GR", SUFFIX: 3, YEAR: 3},
       1:{CODE: "GR4", PREFIX: "GR", SUFFIX: 4, YEAR: 2},
       2:{CODE: "GR1", PREFIX: "GR", SUFFIX: 1, YEAR: 5},
       3:{CODE: "GR2", PREFIX: "GR", SUFFIX: 2, YEAR: 4}
    }
};
var sortable = [];
for (let p in obj.PARTS) {
    sortable.push(obj.PARTS[p]);
}
obj.PARTS = sortable.sort(function(a, b) {
    return a.SUFFIX > b.SUFFIX;
});

现在你的 obj 的嵌套部分根据 SUFFIX 升序排序

【讨论】：