如何使用键遍历对象并获取值

Question

所以我不知道为什么我在这方面遇到这么困难，但我有一个对象我正试图映射它以从中获取值。

例如：

let obj = {
      "lyzjmpkvbtocygakcoxu": {
        "label": "Show Time",
        "hour": "12",
        "minute": "00",
        "period": "p.m.",
        "add_time": "enabled",
        "bdlmynfythqgyzrhruhw_add_date": "December 01, 2021",
        "bdlmynfythqgyzrhruhw_stock": ""
      },
      "eueuuzvkteliefbnwlii": {
        "label": "Show Time",
        "hour": "05",
        "minute": "00",
        "period": "p.m.",
        "add_time": "enabled",
        "brtmypzvuooqhvqugjbj_add_date": "December 02, 2021",
        "brtmypzvuooqhvqugjbj_stock": ""
      }
    }

我希望能够得到这个：

December 01, 2021, December 02, 2021

我能够这样做来获取“add_time”的值和键，但是我想要的是包含“..._add_date”的键的值。

Object.keys(obj).reduce(
          (acc, elem) => {
            acc[elem] = obj[elem].add_time;
            return acc;
          },
          {},
        );

Answer 1

我想你可以搜索键和 .find 匹配模式的那个...

let obj = {
      "lyzjmpkvbtocygakcoxu": {
        "label": "Show Time",
        "hour": "12",
        "minute": "00",
        "period": "p.m.",
        "add_time": "enabled",
        "bdlmynfythqgyzrhruhw_add_date": "December 01, 2021",
        "bdlmynfythqgyzrhruhw_stock": ""
      },
      "eueuuzvkteliefbnwlii": {
        "label": "Show Time",
        "hour": "05",
        "minute": "00",
        "period": "p.m.",
        "add_time": "enabled",
        "brtmypzvuooqhvqugjbj_add_date": "December 02, 2021",
        "brtmypzvuooqhvqugjbj_stock": ""
      }
    }
const result = Object.values(obj)
  .map(val =>
    Object.entries(val)
      .find(([key]) => key.endsWith('_add_date'))
      [1]
  )
  .join(', ');
console.log(result);

但更好的方法是修复上游代码，这样一开始就不会创建如此奇怪的结构。