根据另一个对象数组的属性值对数组进行排序

Question

假设我有一个对象数组：

var list = [
       { name: "A", distance: 1},
       { name: "B", distance: 2},
       { name: "C", distance: 3},
       { name: "D", distance: 4},
       { name: "E", distance: 5},
       { name: "F", distance: 6},
       { name: "G", distance: 7},
       { name: "H", distance: 8} 
    ];

如果我有另一个像这样的数组：

var disturbed = ["G", "B", "C", "F"];

如何根据distance property 从list array 对disturbed array 进行排序，如下所示：

["B", "C", "F", "G"];

编辑：我试过这段代码没有成功：

items = [ 
       { name: "A", distance: 1},
       { name: "B", distance: 2},
       { name: "C", distance: 3},
       { name: "D", distance: 4},
       { name: "E", distance: 5},
       { name: "F", distance: 6},
       { name: "G", distance: 7},
       { name: "H", distance: 8}
]

sorting = [ 1, 2,3,4,5,6,7,8,9,10 ];
result = []
for (let i = 0; i < items.length; i++){
sorting.forEach(function(key) {
    var found = false;
    items = items.filter(function(item) {

        if(!found && items[i].distance == key) {
            result.push(item);
            found = true;
            return false;
        } else 
            return true;
    })
})

result.forEach(function(item) {
    document.writeln(item[i]) 
})
}

如何根据另一个对象数组的属性值对数组进行排序

Answer 1

您可以使用.reduce()将list数组更改为对象，然后根据该对象进行排序。

演示：

var list = [
       { name: "A", distance: 1},
       { name: "B", distance: 2},
       { name: "C", distance: 3},
       { name: "D", distance: 4},
       { name: "E", distance: 5},
       { name: "F", distance: 6},
       { name: "G", distance: 7},
       { name: "H", distance: 8} 
    ];
    
var disturbed = ["G", "B", "C", "F"];
    
var sort = list.reduce((acc, cur) => {
  acc[cur.name] = cur.distance;
  return acc;
}, {});

disturbed.sort((a, b) => sort[a] - sort[b]);

console.log(disturbed)

Answer 2

您可以使用sort 方法来做到这一点

var list = [
       { name: "A", distance: 1},
       { name: "B", distance: 2},
       { name: "C", distance: 3},
       { name: "D", distance: 4},
       { name: "E", distance: 5},
       { name: "F", distance: 6},
       { name: "G", distance: 7},
       { name: "H", distance: 8} 
    ];

var disturbed = ["G", "B", "C", "F"];

disturbed.sort((a, b) => {
    var itemA = list.find(item => item.name === a);
    var itemB = list.find(item => item.name === b);
    return itemA.distance - itemB.distance;
});

disturbed.forEach(function(item) {
    document.writeln(item[i]) 
})

Answer 3

您可以使用.find() 查找具有指定name 属性且与distributed 中的元素匹配的对象。一旦你得到这个，你就可以得到距离属性并计算差异以进行相应的排序：

const list = [
  { name: "A", distance: 1},
  { name: "B", distance: 2},
  { name: "C", distance: 3},
  { name: "D", distance: 4},
  { name: "E", distance: 5},
  { name: "F", distance: 6},
  { name: "G", distance: 7},
  { name: "H", distance: 8} 
];

const disturbed = ["G", "B", "C", "F"];

const res = disturbed.sort((a, b) => {
  const {distance: d_a} = list.find(({name}) => name === a);
  const {distance: d_b} = list.find(({name}) => name === b);
  return d_a - d_b;
});

console.log(res);

更有效的方法是使用.map() 创建new Map，然后在地图上的键上使用.sort()：

const list = [
  { name: "A", distance: 1},
  { name: "B", distance: 2},
  { name: "C", distance: 3},
  { name: "D", distance: 4},
  { name: "E", distance: 5},
  { name: "F", distance: 6},
  { name: "G", distance: 7},
  { name: "H", distance: 8} 
];
const disturbed = ["G", "B", "C", "F"];

const lut = new Map(list.map(({name, distance}) => [name, distance]));
const res = disturbed.sort((a, b) => lut.get(a) - lut.get(b));
console.log(res);