可以在 django 形式中合并选择标签吗？

Question

我有一个在 html 页面上呈现的 django 表单，并且我有一个执行过滤功能的选择下拉菜单。我想知道是否可以将此选择标签合并为我的表单的一部分？我希望选择标签成为 routestep_form 的一部分。

                  <center>        
                  <form class ="subtitle" method = 'POST' action="{% url 'buildpage:partrequestinfo' %}" enctype="multipart/form-data">{% csrf_token %}
                  {{routestep_form.as_p}}

                  <select name = "myselect" id="id_step" onchange="getOptions(this.value)">
                  <option value="-----">-----</option>
                  {% for step in steps %}
                  <option value="{{ step }}">{{ step }}</option>
                  {%  endfor %}
                  </select>
                  <br/><br/>
                  <select id="id_step_option">
                  <option value="-----">-----</option>
                  </select>

                  <input type='submit' value='Next'/>
                  </form>
                  </center> 

我的表格：

class RouteStepForm(forms.ModelForm):

    class Meta:
        model = RouteStep
        fields = '__all__'
        widgets = {
            'step': Select,
            'step_option': Select,
        }

        error_messages = {
            NON_FIELD_ERRORS: {
                'unique_together': "%(RouteStep)s %(description)s are not unique.",
            }
        }

视图：其他表单是我在同一页面上的表单，但我主要关注的是 RouteStepForm。

def partrequestinfo(request):
    steps = Step.objects.all()
    if not request.user.is_staff or not request.user.is_superuser:
        raise Http404
    req_form = PartRequestForm(request.POST or None, request.FILES or None)
    step_form = StepForm(request.POST or None, request.FILES or None)
    stepoption_form = StepOptionForm(request.POST or None, request.FILES or None)
    routestep_form = RouteStepForm(request.POST or None, request.FILES or None)

    if req_form.is_valid() and step_form.is_valid() and stepoption_form.is_valid() and routestep_form.is_valid():
            instance = req_form.save(commit=False)
            instance.user = request.user
            instance.save()
            step = step_form.save(commit=False)
            step.save()
            stepoption = stepoption_form.save(commit=False)
            stepoption.save()
            routestep = routestep_form.save(commit=False)
            routestep.save()
            messages.success(request, "Successfully Created")
            return HttpResponseRedirect(instance.get_absolute_url())
    else: 
        context = {
                "req_form": req_form,
                "step_form": step_form,
                "stepoption_form": stepoption_form,
                "routestep_form": routestep_form,
                "steps": steps,
        }

    return render(request, "buildpage/partrequestinfo.html", context)

型号：

class Step(models.Model):
    name = models.CharField(_('Step Name'), max_length=100, default='')
    def __unicode__ (self):
            return self.name

class StepOption(models.Model):
    step = models.ForeignKey(Step, related_name = 'Step', null = True)
    name = models.CharField(_('Step Option'), max_length=100, default='')
    def __unicode__ (self):
            return self.name + " - " + self.step.name

class RouteStep(models.Model):
    step_number = models.PositiveIntegerField(_('Step Number'), default = 0)
    step =  models.ForeignKey(Step, related_name = 'Step+', null = True)    
    step_option = models.ForeignKey(StepOption, related_name = 'StepOption', null=True)
    def __unicode__ (self):
            return self.step_option

Answer 1

试试：

class RouteStepForm(forms.ModelForm):
    def __init__(self, *args, **kwargs):
        super(forms.ModelForm, self).__init__(*args, **kwargs)
        self.fields['step'].widget.choices=[ query.name for query in Step.objects.all()]) 

如果它不起作用，请发布您显示的模板代码。

编辑

我编辑了我的答案，也发现这很有帮助。Why do I get an object is not iterable error? 和这个Getting object not iterable error in django form。

另一个解决方案是Can not iterate a ChoiceField with Select as widget