【发布时间】:2015-05-07 17:18:35
【问题描述】:
我试图在同一页面上放置 2 个 HTML 表单,然后使用 JavaScript 来控制他们提交到的目标 .php 文件,基于该文件按下 submit 按钮。
目前,它正在发送到正确的 php/email 地址,但也将用户从页面中带走——这是我想要阻止的。
任何帮助将不胜感激。这是我的 HTML:
<div class="col-md-6">
<form class="form" id="ajax-contact-form" action="multi/sendmail.php">
<div class="controls">
<div class="input-prepend">
<span class="add-on"><i class="fa fa-user"></i></span>
<input type="text" name="contact_name" id="contact_name" class="form-control" placeholder="Name" required>
</div>
</div>
<div class="controls">
<div class="input-prepend">
<span class="add-on"><i class="fa fa-envelope"></i></span>
<input name="contact_email" id="contact_email" type="email" class="form-control" placeholder="Email" required>
</div>
</div>
<textarea name="contact_message" id="contact_message" placeholder="Message" rows="8" class="form-control" required></textarea>
<div class="controls send">
<button type="submit" class="btn-primary btn-lg" value="Submit1" id="submit2" onClick="mainform">Send</button>
<div class="loading"></div>
<div class="results"></div>
</div>
</form>
</div>
<!--FORM 2-->
<div class="col-md-6">
<form class="form2" id="ajax-contact-form2" action="multi/sendmail2.php">
<div class="controls">
<div class="input-prepend">
<span class="add-on"><i class="fa fa-user"></i></span>
<input type="text" name="contact_name" id="contact_name" class="form-control" placeholder="Name" required>
</div>
</div>
<div class="controls">
<div class="input-prepend">
<span class="add-on"><i class="fa fa-envelope"></i></span>
<input name="contact_email" id="contact_email" type="email" class="form-control" placeholder="Email" required>
</div>
</div>
<textarea name="contact_message" id="contact_message" placeholder="Message" rows="8" class="form-control" required></textarea>
<div class="controls send">
<button type="submit" class="btn-primary btn-lg" value="Submit2" id="submit2" onClick="form2">Send</button>
<div class="loading"></div>
<div class="results"></div>
</div>
</form>
</div>
<!--/FORM 2-->
这是我的 JavaScript:
function mainform() {
e.preventDefault();
$('.loading').show();
$.post('multi/sendmail.php', $('.form').serialize(), function(data) {
$('.results').html(data);
}).success(function() {
$('.loading').hide();
})
}
function form2() {
e.preventDefault();
$('.loading').show();
$.post('multi/sendmail2.php', $('.form2').serialize(), function(data) {
$('.results').html(data);
}).success(function() {
$('.loading').hide();
})
}
这是我的旧 JavaScript,它有效:
$('form').submit(function(e) {
e.preventDefault();
$('.loading').show();
$.post('multi/sendmail.php', $('.form').serialize(), function(data){
$('.results').html(data);
}).success(function(){
$('.loading').hide();
})
})
还有一个 PHP 文件:
<?php
$name = isset($_REQUEST['contact_name']) ? $_REQUEST['contact_name'] : '' ;
$email = isset($_REQUEST['contact_email']) ? $_REQUEST['contact_email'] : '' ;
$message = isset($_REQUEST['contact_message']) ? $_REQUEST['contact_message'] : '' ;
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type: text/html; charset=iso-8859-1" . "\r\n";
$headers .= "From:".$name." ".$email;
// Replace mail@website.com with your email
mail( "me@email.com", "Message from My Future Now Website",$message, $headers );
print "<strong>Form submitted successfully.</strong>";
?>
我做错了什么?
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标签: javascript php html forms