匹配包含 Javascript 中特定字符串的字符串中的字符串

Question

抱歉标题太糟糕了 - 不知道怎么写才好。

注意： 我正在尝试在 Javascript 中执行此操作

我想匹配 2 个不同长度和结构的 url 中的特定文本。一个以video 开头，另一个以audio 开头。必须根据字符串的开头以不同的方式替换匹配项。

我不知道如何在积极的后视中进行 dotall (.*) 匹配？

例如，下面的字符串应该由两个独立的正则表达式匹配，一个指定video，另一个指定audio必须在%7bmatch%7d之前 它们必须仅匹配%7bmatch%7d 的给定字符串开头。

video://lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length

audio://lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length

我尝试过： /(?<=video)(?<=.*)%7bmatch%7d/ghttp://regexr.com?373gh 在其他变体中，似乎不能完全匹配%7bmatch%7d 或任何其他匹配，而没有得到示例中video 以来的所有内容。 把我难住了，真的很感激朝着正确的方向轻推。

编辑：针对 Javascript 的回答：

// Random collection of string(s)
var inputString = "video://lots0fr@ndomcharacasdf/asd/ft#Rsinbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthaudio://lots0fr@ndomcharact#Rsinbet/asdfas/dweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthvideo://lots0fr@ndomcharact#Rsinbetweasdf/asd/f/asdfenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthaudio://lots0fr@ndomcharaasdfafsdct#Rsinbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthvideo://lots0fr@ndomcharact#Rsinfasdfasdfbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthaudio://lots0fr@ndomcharaasdfasdf///asdfasdfct#Rsinbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length";



// Regex to match after every `video` occurence
regexVideo = new RegExp(/(video.*?)%7bmatch%7d/g);

// Regex to match after every `audio` occurence
regexAudio = new RegExp(/(audio.*?)%7bmatch%7d/g);

// strings to replace the matches
var replaceStringVideo = "<span class='woot'>W00tW00tVideoW00t</span>";
var replaceStringAudio = "<span class='woot'>W00tW00tVAudioW00t</span>";

// replace both audio and video with respective replace values NOTE: the dollar token needed concatenated before the replaceString.
inputString.replace(regexVideo, "$1" + replaceStringVideo).replace(regexAudio, "$1" + replaceStringAudio);

// This yields an inputString value of 
"video://lots0fr@ndomcharacasdf/asd/ft#Rsinbetweenof1nd1scrimin@length/<span class='woot'>W00tW00tVideoW00t</span>/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthaudio://lots0fr@ndomcharact#Rsinbet/asdfas/dweenof1nd1scrimin@length/<span class='woot'>W00tW00tVAudioW00t</span>/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthvideo://lots0fr@ndomcharact#Rsinbetweasdf/asd/f/asdfenof1nd1scrimin@length/<span class='woot'>W00tW00tVideoW00t</span>/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthaudio://lots0fr@ndomcharaasdfafsdct#Rsinbetweenof1nd1scrimin@length/<span class='woot'>W00tW00tVAudioW00t</span>/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthvideo://lots0fr@ndomcharact#Rsinfasdfasdfbetweenof1nd1scrimin@length/<span class='woot'>W00tW00tVideoW00t</span>/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@lengthaudio://lots0fr@ndomcharaasdfasdf///asdfasdfct#Rsinbetweenof1nd1scrimin@length/<span class='woot'>W00tW00tVAudioW00t</span>/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length"

Answer 1

如果您使用的是 PHP 或 Perl，那么您可以使用 \K 锚点来忽略正则表达式中匹配的所有内容，如下所示：

video.*\K%7bmatch%7

不幸的是，在 JavaScript 中，最简单的方法是使用以下正则表达式来匹配从视频到 %7bmatch%7d 的所有内容，然后您可以使用 replace() 删除不需要的数据：

var input = "video://lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length";
var finalResult = /(?=video.*%7bmatch%7d).*%7bmatch%7d/.exec(input)[0].replace(/.*(?=%7bmatch%7d)/, "");
console.log(finalResult);

Regex101 Demo

Answer 2

看起来像那个网站上的一个错误。您应该使用/(?<=video.*)%7b.*?%7d/g，但该网站似乎认为它是向前看，而不是向后看（您可以通过将鼠标悬停在任一括号上来检查它）。

---

如果您需要匹配 %7b.*?%7d 来替换它，只需匹配所有内容并在替换中引用它，如下所示：

s/^(video.*?)%7b.*?%7d/$1your_replacement_here/g

见demo on regexr.com 和另一个demo on regex101.com。

Answer 3

这个正则表达式怎么样：

var regExpVideo = /(?:video):\/\/[^%]+([^\/]+)/
var regExpAudio = /(?:audio):\/\/[^%]+([^\/]+)/
var videoSource = regExpVideo.exec("video://lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length")[1];
var audioSource = regExpAudio.exec("audio://lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length/%7bmatch%7d/lots0fr@ndomcharact#Rsinbetweenof1nd1scrimin@length")[1];

希望这会有所帮助，

问候，

马塞洛