从长度 < 16 的数组字符串生成

Question

我有这个数组["Brad", "came", "to", "dinner", "with", "us"]

Brad came to dinner with us (27 chars > 16) 所以我需要将其拆分为 2 个字符串：

Brad came to
dinner with us

单词不能切片

let inpt=["Brad", "came", "to", "dinner", "with", "us"]
op=[]
for(i of inpt) if (op.join('').length+i.length <16) {op.push(i)} else break
console.log(op.join(' '))

这将返回我的第一部分，但如果我的输入数组（字符串）长于 16+16+16...，我如何获得第二部分和其他部分......

Answer 1

空格连接后，使用正则表达式匹配最多16个字符，后跟空格或字符串结尾：

let inpt=["Brad", "came", "to", "dinner", "with", "us"];
const str = inpt.join(' ');
const matches = str.match(/.{1,16}(?: |$)/g);
console.log(matches);

Answer 2

也可以通过 Array.reduce 来完成：

let inpt=["Brad", "came", "to", "dinner", "with", "us"];

let out = inpt.reduce((acc, el) => {
  let l = acc.length;
  if (l === 0 || (acc[l - 1] + el).length > 15) {
    acc[l] = el;
  } else {
    acc[l - 1] += " " + el;
  }
  return acc;
}, []);

console.log(out);