仅在当前未运行时启动应用程序

Question

我正在向用户发送推送通知，点击它会打开应用程序。

我的问题是当应用程序已经打开时，点击通知再次启动应用程序。

我只希望它在应用尚未运行时启动它。

我在通知中使用 Pending Intent：

PendingIntent contentIntent = PendingIntent.getActivity(this, 0, new Intent(this, Splash.class), 0);

我看到帖子说使用：

<activity 
android:name=".Splash"
android:launchMode="singleTask"

但问题是我正在运行的应用程序正在运行其他活动，然后在应用程序启动 7 秒后完成的启动画面，所以当应用程序运行时，启动画面不是当前活动

Answer 1

为您的应用使用“启动Intent”，如下所示：

PackageManager pm = getPackageManager();
Intent launchIntent = pm.getLaunchIntentForPackage("your.package.name");
PendingIntent contentIntent = PendingIntent.getActivity(this, 0, launchIntent, 0);

将“your.package.name”替换为 Android 清单中的包名称。

此外，您应该从清单中删除特殊的 launchMode="singleTask"。标准的 Android 行为将满足您的需求。

Answer 2

String appPackageName = "";

private void isApplicationInForeground() throws Exception {
    ActivityManager am = (ActivityManager) getSystemService(ACTIVITY_SERVICE);
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {
        final List<ActivityManager.RunningAppProcessInfo> processInfos = am
                .getRunningAppProcesses();
        ActivityManager.RunningAppProcessInfo processInfo = processInfos
                .get(0);
        // for (ActivityManager.RunningAppProcessInfo processInfo : processInfos) {
        if (processInfo.importance == ActivityManager.RunningAppProcessInfo.IMPORTANCE_FOREGROUND) {
            // getting process at 0th index means our application is on top on all apps or currently open 
            appPackageName = (Arrays.asList(processInfo.pkgList).get(0));
        }
        // }
    }
    else {
        List<ActivityManager.RunningTaskInfo> taskInfo = am.getRunningTasks(1);
        ComponentName componentInfo = null;
        componentInfo = taskInfo.get(0).topActivity;
        appPackageName = componentInfo.getPackageName();
    }
}

private void notifyMessage(String text) {
    if (appPackageName.contains("com.example.test")) {
        // do not notify
    }
    else {          
        // create notification and notify user  
    }
}

Answer 3

对于使用 Xamarin.Android 的用户。 David Wasser 的答案的 Xamarin 版本如下：

        //Create notification
        var notificationManager = GetSystemService(Context.NotificationService) as NotificationManager;
        Intent uiIntent = PackageManager.GetLaunchIntentForPackage("com.company.app");

        //Create the notification
        var notification = new Notification(Android.Resource.Drawable.SymActionEmail, title);

        //Auto-cancel will remove the notification once the user touches it
        notification.Flags = NotificationFlags.AutoCancel;

        //Set the notification info
        //we use the pending intent, passing our ui intent over, which will get called
        //when the notification is tapped.
        notification.SetLatestEventInfo(this, title, desc, PendingIntent.GetActivity(this, 0, uiIntent, PendingIntentFlags.OneShot));

        //Show the notification
        notificationManager.Notify(0, notification);

Answer 4

不是在点击通知时显示 Splash 活动，而是显示您的 MainActivity，因为您的 Splash 活动将在一段时间后关闭，但 MainActivity 将保持打开状态并且

<activity 
android:name=".MainActivity"
android:launchMode="singleTask"

Answer 5

使用 Splash 作为 Fragment 而不是 Activity。保留 Splash 片段（7 秒），将其替换为所需的片段（着陆页）。

将 launchMode="singleTask" 添加到清单中。

正如Rahul 所述，如果应用程序已经在运行，则调用onNewIntent()，否则onCreate()

@Override
protected void onNewIntent(Intent intent) 
{   
    super.onNewIntent(intent);
}

或

选择David 的答案，看起来很有希望。

Answer 6

当点击通知并且您的代码重定向到您想要的屏幕时，只需通过调用此方法替换该代码并根据“真/假”结果重定向到特定屏幕。

    private boolean isAppOnForeground(Context context) {
    ActivityManager activityManager = (ActivityManager) context.getSystemService(Context.ACTIVITY_SERVICE);
    List<RunningAppProcessInfo> appProcesses = activityManager.getRunningAppProcesses();
    if (appProcesses == null) {
      return false;
    }
    final String packageName = context.getPackageName();
    for (RunningAppProcessInfo appProcess : appProcesses) {
      if (appProcess.importance == RunningAppProcessInfo.IMPORTANCE_FOREGROUND && appProcess.processName.equals(packageName)) {
        return true;
      }
    }
    return false;
  }

Answer 7

Intent.FLAG_ACTIVITY_BROUGHT_TO_FRONT

也许不要启动 Splash Activity 并重新打开（带到前面） MainActivity 并使用一个侦听器更新 UI，该侦听器告诉您您有一个新通知（带有标志 - 布尔值或要制作的界面）一个听众）。

Answer 8

您可以使用有序广播来完成此操作。

1) 将您的PendingIntent 更改为启动BroadcastReceiver，这将决定是启动活动还是什么都不做：

PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, new Intent(this, DecisionReceiver.class), 0);

2) 创建决策BroadcastReceiver：

public class DecisionReceiver extends BroadcastReceiver {
    @Override
    public void onReceive(Context context, Intent intent) {
        context.sendOrderedBroadcast(new Intent(MainActivity.NOTIFICATION_ACTION), null, new BroadcastReceiver() {
            @Override
            public void onReceive(Context context, Intent intent) {
                if (getResultCode() == MainActivity.IS_ALIVE) {
                    // Activity is in the foreground
                }
                else {
                    // Activity is not in the foreground
                }
            }
        }, null, 0, null, null);
    }
}

3) 在您的活动中创建一个BroadcastReceiver，这将表明它处于活动状态：

public static final String NOTIFICATION_ACTION = "com.mypackage.myapplication.NOTIFICATION";
public static final int IS_ALIVE = 1;
private BroadcastReceiver mAliveReceiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {
        setResultCode(IS_ALIVE);
    }
};

// Register onResume, unregister onPause
// Essentially receiver only responds if the activity is the foreground activity
@Override
protected void onResume() {
    super.onResume();
    registerReceiver(mAliveReceiver, new IntentFilter(NOTIFICATION_ACTION));
}

@Override
protected void onPause() {
    super.onPause();
    unregisterReceiver(mAliveReceiver);
}

Answer 9

notificationIntent.addFlags(Intent.FLAG_ACTIVITY_SINGLE_TOP|Intent.FLAG_ACTIVITY_CLEAR_TOP|Intent.FLAG_ACTIVITY_NEW_TASK);

notificationIntent.putExtras(bundle);
PendingIntent pintent = PendingIntent.getActivity(context, 0, notificationIntent, PendingIntent.FLAG_UPDATE_CURRENT);

Answer 10

如果活动在后台运行，请尝试将其添加到您的意图中以将其置于最前面

Intent intent = new Intent(this, Splash.class); intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT); PendingIntent contentIntent = PendingIntent.getActivity(this, 0, intent, 0);

Answer 11

首先在 Manifest 文件的 Application 元素中设置默认任务 android:taskAffinity="com.example.testp.yourPreferredName"。在您的SplashActivity 上维护您的android:launchMode="singleTask"。现在，由于您的 SplashActivity 是您的主要条目，因此将此代码添加到 onResume()、onNewIntent() 和 onCreate() （再次考虑不推荐 onResume()） - 遵循代码中的 cmets

//Note these following lines of code will work like magic only if its UPVOTED.
//so upvote before you try it.-or it will crash with SecurityException
ActivityManager am = (ActivityManager) this.getSystemService(ACTIVITY_SERVICE);

List< ActivityManager.RunningTaskInfo > taskInfo = am.getRunningTasks(1000);    
    for(int i =0; i< taskInfo.size(); i++){
        String PackageName = taskInfo.get(i).baseActivity.getPackageName();
        if(PackageName.equals("packagename.appname")){// suppose stackoverflow.answerer.Elltz
            //if the current runing actiivity is not the splash activity. it will be 1
            //only if this is the first time your <taskAffinity> is be called as a task
            if(taskInfo.get(i).numActivities >1){
                //other activities are running, so kill this splash dead!! reload!!                 
                finish();
                // i am dying in onCreate..(the user didnt see nothing, that's the good part)
                //about this code. its a silent assassin
            }
            //Operation kill the Splash is done so retreat to base.
            break;
        }
    }

此代码不适用于 api 21+；要使其工作，您需要使用AppTask，这将为您节省额外的代码行，因为您不会在循环中找到您的Task。

希望对你有帮助