【发布时间】:2014-05-20 08:46:11
【问题描述】:
我想实现一件事。我在多个标签中打开了我的网站。当我在一个标签中工作时,其他标签不应该超时。它应该是活着的。如何为其他标签保持活力。我用下面的js查找空闲时间注销。
<script type="text/javascript">
idleTime = 0;
$(document).ready(function () {
//Increment the idle time counter every minute.
var idleInterval = setInterval("timerIncrement()", 60000); // 1 minute
//Zero the idle timer on mouse movement.
$(this).mousemove(function (e) {
idleTime = 0;
});
$(this).keypress(function (e) {
idleTime = 0;
});
})
function timerIncrement() {
idleTime = idleTime + 1;
if (idleTime > 2) { // 30 minutes
var beforeTime = new Date()
var bminutes = beforeTime.getMinutes();
var bseconds = beforeTime.getSeconds();
var user='<?php echo Auth::getSessionUserFullName();?>';
if(user!='')
{
var timehours=beforeTime.getHours();
var timeoutmin=bminutes+1;
var timeoutseconds=bseconds-1;
if(timeoutseconds>59)
{
timeoutseconds=0;
timeoutmin=timeoutmin+1;
}
if(timeoutmin>59)
{
timeoutmin=0;
timehours=hours+1;
}
if(timehours>24)
{
timehours=0;
}
var ok=confirm("Your session expire time started at "+beforeTime.getHours()+":"+beforeTime.getMinutes()+":"+beforeTime.getSeconds()+".Please click 'OK' before "+timehours+":"+timeoutmin+":"+timeoutseconds+" to stay signed in.");
if(ok)
{
var currentTime = new Date()
var aminutes = currentTime.getMinutes();
var aseconds = currentTime.getSeconds();
var time=aminutes-bminutes;
if(aminutes>bminutes && aseconds>bseconds)
{
alert('Time out!!Please login again to access.');
window.location.href='<? echo APPLICATION_WEBROOT?>auth/logout';
return false;
}
else if(time>=2)
{
alert('Time out!!Please login again to access.');
window.location.href='<? echo APPLICATION_WEBROOT?>auth/logout';
return false;
}
else
{
return true;
}
}
else
{
window.location.href='<? echo APPLICATION_WEBROOT?>auth/logout';
}
}
}
}
</script>
请帮助我。如何为所有打开的标签保留会话。提前感谢
【问题讨论】:
-
如果你实现这样的超时(这本身就是一个有问题的选择),那么你根本就不能。浏览器选项卡不知道其他浏览器选项卡。
-
好的。我如何在删除 js 时实现。
标签: javascript php session