在 AngularJS 工厂中访问 $scope？

Question

我是AngularJS的新手，觉得它很有趣，但是我对以下情况有点不清楚。

app.factory('deleteFac', function($http){

var factory = {}; 

factory.edit = function(id){
  $http.get('?controller=store&action=getDetail&id=' + id).
    success(function(data, status){
        /** 
        got an error on the following 
        when i use return data; and i get data undefined 
        in the controller which i get it because its doing a ajax call
        you don't get data until the call first.
        **/
        $scope.detail = data;
      })
    }

return factory;
})

当我分配给$scope 并使用返回数据时出现错误，我是否可以将返回数据分配给$scope？

Answer 1

您通常不会在工厂、服务或提供商中使用$scope。通常，您会返回 promise（由 $http 返回），然后在控制器中处理承诺（您确实有 $scope）。

factory.edit = function(id){
    return $http.get('?controller=store&action=getDetail&id=' + id);
}

控制器功能：

$scope.edit = function(id) {

    deleteFac.edit(id).then(function(response) {
        $scope.something = response.model;
    });
}

Answer 2

我猜你是这个意思：

app.factory('deleteFac', function($http){

  var service = {}; 

   factory.edit = function(id, success, error){
        var promise = $http.get('?controller=store&action=getDetail&id=' + id);
        if(success)
           promise.success(success);
        if(error)
           promise.error(error);
   };

   return service;
});

然后在您的控制器中执行以下操作：

function MyController($scope, deleteFac){
   deleteFac.edit($scope.id, function(data){
       //here you have access to your scope.
   });
}

Answer 3

以下技巧是一个非常糟糕的做法，但如果你赶时间，你可以使用它：

将$scope 替换为：angular.element('[ng-controller=CtrlName]').scope()

Answer 4

就我个人而言，我想使用工厂的作用域，因此，我不会将作用域作为参数从调用 factory.function() 的客户端传递给它。

我在尝试使用 $scope.watch(...) 时也遇到了同样的问题，因为我们不能直接从工厂或服务中使用 $scope，但我想让它以这种方式工作，所以这就是为什么我刚刚更新了我的函数以将范围作为参数并让工厂的客户发送 $scope。所以，这将是我的解决方案：

var app = angular.module("myApp", []);

app.factory('MyFactory', function($http) {

      var factory = {};
      //This is only for my own issue I faced.
      factory.Images = {};

      factory.myFunction = function(id, scope) {
        //This is an example of how we would use scope inside a factory definition
        scope.details = "Initial Value";
        //In my case I was having this issue while using watch
        scope.$watch('details' , function(newValue, oldValue) {
          if(oldValue){
             scope.log = "Details was updated to : " +newValue;
            }
        });
        
        scope.details = "My Id is: "+id;
       };
        return factory;
});

//Controller: Factory's Client.
app.controller("MyController", ['$scope', 'MyFactory', function($scope, MyFactory) {
  
        MyFactory.myFunction(5, $scope);
}]);

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myApp" ng-controller="MyController">
  <span>{{details}} </span>
  <hr>
  <p>{{log}} </p>
</div>

我希望这会有所帮助。 问候。

Answer 5

我认为这是最干净的解决方案：

如果有问题或改进，请告诉我。

(function(){
  angular.controller('controllerName', controllerName);
  controllerName.$inject = ['$scope', factory];

  function controllerName($scope, factory){
    var vm = this;

    vm.data = factory.alertPopup();
  }

  angular.factory('factory', factory);
  factory.$inject = ['externalServices'];

  function factory(externalServices){
    return {
      returnData : returnData
    }

    function returnData(){
      return externalServices.whatever();
    }
  }
})();

Answer 6

.factory('POPUP', function($ionicLoading, $ionicPopup) {
  var self = this;
  // THIS BLOCK SCREEN ! for loading ! Be carefoull !! ( deprecated: assign this to a var for security)
  self.showLoading = function(title, message, scope){
  scope.loading = true;
  return $ionicLoading.show({ content: message, showBackdrop: false });
  };
  self.hideLoading = function(title, message, scope){
  scope.loading = false;
  return $ionicLoading.hide();
};

// NOT BLOCK SCREEN- SIMPLE ALERTS - Standards popups
self.showAlert = function(title, message, callback){
  var alertPopup = $ionicPopup.alert({ title: title, template: message });
  alertPopup.then(function(res) {
      console.log('callback popup');
      if (callback){ callback(); }
  });
};
 self.showConfirm = function(objectPopup, callback){
 if (objectPopup === undefined){ objectPopup = { title: 'test confirm    Popup', template: 'Message test Confirm POPUP' }; }
 var alertPopup = $ionicPopup.confirm(objectPopup);
 alertPopup.then(function(res) {
   if (res) { callback(true); }
    else { callback(false); }
 });
 };
   return self;
   }) 

Answer 7

我知道这个问题很老，但这对我有用

app.factory('myFactory',function(){

    let toRet = {
        foo: foo
    }

    return toRet;

    function foo(){ // This function needs to use passed scope.
        let $scope = toRet.$scope;
        // Do stuff with $scope.
    }
});

app.controller('myController',function($scope,myFactory){

    myFactory.$scope = $scope;
    /*
        We could just pass $scope as a parameter to foo, but this is
        for cases where for whatever reason, you cannot do this.
    */
    myFactory.foo();

});