用python编写的def函数中的加密代码

Question

在以下代码中需要一些帮助，因为它进入无限循环并且不验证用户输入：get_offset 是函数。刚刚编辑需要一些帮助，以在定义的函数中完成加密部分

def get_offset(offset):
    while True:
        value = (offset)
        if value < 1:
            print("")
        if value > 94:
            print("")
    return offset

my_details = display_details()

get_choice = get_menu_choice()

print(my_details)
print(get_choice)

count = 10

while count > 0:

    count -=1

    encrypted = ""

    choice = int(input("What would you like to do [1,2,3,4,5]: "))

    while choice <1 and choice > 5:
        print("Invalid choice, please enter either 1, 2, 3, 4 or 5.")

    if choice == 1:
        string_input = input("Please enter string to encrypt: ")
        input_offset = get_offset(int(input("Please enter offset value (1 to 94): ")))

   **for letter in string_input:
        x = ord(letter)
        encrypted += chr(x + input_offset)
        if x < 32:
            x += 94
        if x > 126:
            x -= 94

    print(encrypted)**

Answer 1

您必须在内部 while 循环中分配 choice 新值。这样，在一次又一次迭代之前会考虑新的输入。

这应该可以解决问题：

while choice < 1 and choice > 5:
    choice = int(input("Invalid choice, please enter either 1, 2, 3, 4 or 5."))

一个随机的建议：如果你想保持数据集严格等于 [1,2,3,4,5]，你应该避免choice<1 和choice>5。这使您的程序容易受到无效输入的影响，例如3.5。

相反，您应该这样做：

valid_inputs = [1, 2, 3, 4, 5]

choice = int(input("Pick a number from [1, 2, 3, 4, 5]:"))

while choice not in valid_inputs:
    choice = int(input("Invalid choice, please enter either 1, 2, 3, 4 or 5."))

<rest of stuff here>

我从您的 cmets 了解到的是，在 get_offset() 中，您希望用户输入一个介于 1 和 94 之间的值。如果用户输入的内容超出该范围，您就想一次又一次地提问。下面的代码应该做你想做的：

def get_offset():
   # first, ask for a value.
   offset = int(input("Enter a value between 1 and 94:"))
   while offset < 1 and offset > 94:
      # if the value is invalid, trap user inside this while loop.
      # user will be stuck here (while loop will return true) 
      # until a valid input is received.
      offset = int(input("Invalid input. Please enter a value between 1 and 94:"))
   # if we proceed down here, it means we are over while loop 
   # and it implies that user has given us valid input. return value.
   return offset

其次，在主while循环中，你可以像这样调用get_offset()：

if choice == 1:
    string_input = input("Please enter string to encrypt: ")
    input_offset = get_offset()