如何遍历两个数组并删除匹配的值

Question

我正在尝试在我的 Ruby on Rails 程序中迭代两个数组，并使用不应排除的对象创建一个新数组。

这是我需要迭代的对象数组：

[#<Result id: 1437, network_host_test_id: 1320, issue_id: 50231, created_at: "2016-04-14 19:30:22", updated_at: "2016-04-27 18:08:00", deleted_at: nil>,
 #<Result id: 1438, network_host_test_id: 1320, issue_id: 47573, created_at: "2016-04-14 19:30:22", updated_at: "2016-04-14 19:30:22", deleted_at: nil>,
 #<Result id: 1439, network_host_test_id: 1320, issue_id: 39758, created_at: "2016-04-14 19:30:22", updated_at: "2016-04-14 19:30:22", deleted_at: nil>,
 #<Result id: 1441, network_host_test_id: 1320, issue_id: 47574, created_at: "2016-04-14 19:30:22", updated_at: "2016-04-14 19:30:22", deleted_at: nil>,
 #<Result id: 1442, network_host_test_id: 1320, issue_id: 50442, created_at: "2016-04-14 19:30:22", updated_at: "2016-04-14 19:30:22", deleted_at: nil>,
 #<Result id: 1443, network_host_test_id: 1320, issue_id: 40991, created_at: "2016-04-14 19:30:22", updated_at: "2016-04-14 19:30:22", deleted_at: nil>,
 #<Result id: 1444, network_host_test_id: 1320, issue_id: 43896, created_at: "2016-04-14 19:30:22", updated_at: "2016-04-14 19:30:22", deleted_at: nil>]

我的排除数组是：

[#<DeferredIssue id: 1, defer_reason: "Test for issue", defer_name: "JF", issue_id: 50231, created_at: "2016-04-28 17:50:37", updated_at: "2016-04-28 17:50:37", network_host_id: 76>,
 #<DeferredIssue id: 2, defer_reason: "Defer a 10", defer_name: "Travis", issue_id: 43896, created_at: "2016-04-28 17:51:25", updated_at: "2016-04-28 17:51:25", network_host_id: 76>]

最后，我的数组不应该有 issue_id 的 50231 或 43896 的对象。

我最初使用exclude? 对此进行了测试，但我的排除数组只是[50231, 43896]。既然它们是对象，那么这种类型的迭代就行不通了。

什么是 Ruby 方法来做这种事情？

Answer 1

您可以使用map 将数组转换为issue_ids 的数组：

ids = exclude_array.map(&:issue_id)
#=> [50231, 43896]
your_objects.select {|o| ids.exclude?(o.issue_id) }