【问题标题】:Character Array Conversion to 2D integer array Failure字符数组转换为二维整数数组失败
【发布时间】:2015-09-15 22:09:15
【问题描述】:

我似乎无法将字符数组转换为二维整数数组。具体如下:

我想将包含特定分隔符的字符数组转换为多维数组,其中每一行的结尾由字符数组中的分隔符指定(我已经用不同的方法确保每一行都有长度相同)。

数组只包含 0 和 1。

问题在于,在测试方法时,它(方法)似乎跳过了一行 - 读取第一行,下一行是 0,读取第三行,第四行是 0。

这些是方法(有问题的方法和测试方法):

    /// <summary>
    /// Converts a character array to 2D int array, where each character is a digit and only the digits of 1 and 0 are 
    /// allowed.
    /// </summary>
    /// <returns>The 2D int array.</returns>
    /// <param name="charArray">Character array.</param>
    /// <param name="delimiter">Delimiter.</param>
    public int[,] ConvertCharArrayTo2DIntArray(char[] charArray, char delimiter){
        int columnCounter = 0;
        //count how many rows
        while (charArray [columnCounter] != delimiter) {
            columnCounter++;
        }

        //count how many lines taking into account the delimiter
        int rows = charArray.Length/(columnCounter+1);

        int[,] twoDimArray = new int[rows, columnCounter];

        //count
        int h = 0;
        for (int i = 0; i < rows; i++) {
            for (int j = 0; j < columnCounter; j++) {
                if (charArray [h] != '\n') {
                    twoDimArray [i, j] = (int)Char.GetNumericValue(charArray [h]);
                    //throw exception if the array contains numbers other than 1 or 0
                    if (twoDimArray [i, j] != 1 && twoDimArray [i, j] != 0)
                        throw new ArgumentException ();
                    h++;
                } else {
                    h++;
                    break;
                }
            }
        }
        return twoDimArray;
    }

这是测试方法:

    [Test()]
    public void TestConvertCharArrayTo2DIntArray(){
        HelperClass hc = new HelperClass ();
        int[,] twoDimArrayExpected = new int[,]{ 
            { 0, 1, 0, 1, 0 },
            { 0, 1, 0, 1, 0 },
            { 0, 1, 0, 1, 0 },
            { 0, 1, 0, 1, 0 } };
        char[] charArray = new char[] {'0','1','0','1','1','\n','1','1','1','1','1','\n','0','1','1','1','0','\n','0','1','0','1','0','\n'};
        int[,] twoDimArrayActual = hc.ConvertCharArrayTo2DIntArray (charArray, '\n');
        for (int i = 0; i < twoDimArrayExpected.GetLength (0); i++) {
            for (int j = 0; j < twoDimArrayExpected.GetLength (1); j++) {
                Console.Write (twoDimArrayActual [i,j]);
                //Commented out because it throws exceptions                                 
                //Assert.AreEqual(twoDimArrayExpected[i,j],
                //twoDimArrayActual[i,j]);
                if (j == twoDimArrayExpected.GetLength (1) - 1) {
                    Console.Write ("\n");
                }
            }
        }
    }

输出是这样的:

01011

00000

11111

00000

我可能只是被卡住了,但现在我真的想不通。

【问题讨论】:

    标签: c# arrays multidimensional-array character


    【解决方案1】:

    当内部循环结束时,您将位于分隔符上。这是您需要跳过增加控制变量 h 的字符分隔符的地方

    正如您现在所做的那样,您增加了控制变量,但随后您跳出了内部循环。但是,仅删除中断指令是行不通的,因为退出内部循环会增加外部循环的控制变量i,从而使每个偶数行都为空且未处理

    你可以尝试修复你的代码

    int h = 0;
    for (int i = 0; i < rows; i++)
    {
        for (int j = 0; j < columnCounter; j++)
        {
            twoDimArray[i, j] = (int)Char.GetNumericValue(charArray[h]);
            //throw exception if the array contains numbers other than 1 or 0
            if (twoDimArray[i, j] != 1 && twoDimArray[i, j] != 0)
                throw new ArgumentException();
            h++;
        }
        h++;
    }
    

    【讨论】:

      【解决方案2】:

      如果你使用列表对象真的很容易

       List<List<int>> twoDimArrayExpected = new List<List<int>>() { 
                     new List<int>() { 0, 1, 0, 1, 0 },
                     new List<int>(){ 0, 1, 0, 1, 0 },
                     new List<int>(){ 0, 1, 0, 1, 0 },
                     new List<int>(){ 0, 1, 0, 1, 0 } };
      
                  string resutls = string.Join("\n", twoDimArrayExpected.Select(x => string.Join("", x)));​
      

      【讨论】:

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