插入 MySQL 之前的 MySQL 日期范围检查

Question

这不是一个重复的问题，我在小提琴演示中的查询处理了数据库中的重叠日期。我所追求的是一种在将日期插入 MySQL 之前在日期范围 $startdate 和 $enddate 上运行查询的方法。基本上我想检查每个员工在那年的假期权利中是否有足够的假期。

我尝试在插入 MYSQL 之前检查日期范围内的每个日期在哪一年。每个员工每年从不同的一天开始

Eg. jon started on 2013-10-10 so his year is  
2013-10-10 to 2014-10-10 
2014-10-10 to 2015-10-10

目前，我的查询检查它们已插入 MYSQL (h.date) 的日期，e.startdate 从它们开始每年计算。在插入日期之前，我应该检查 $startdate、$enddate 之间的每个日期。

我已经设置了一个 Fiddle 演示，当日期已经在数据库中时它可以工作

$startdate ='2015-10-05';
$enddate ='2015-10-20';

    SELECT 
            e.name AS Employee,
            CONCAT(
                CEIL(DATEDIFF(h.date, e.startdate)/365), 
                ' (',
                DATE_ADD(e.startdate, INTERVAL FLOOR(DATEDIFF(h.date, e.startdate)/365) YEAR), ' to ',        
                DATE_ADD(e.startdate, INTERVAL CEIL(DATEDIFF(h.date, e.startdate)/365) YEAR),
                ')'
                ) as Year,
            COUNT(h.date) AS Holidays_Taken,
            SUM(h.hours) AS Hours
        FROM employees AS e
        LEFT JOIN holidays_taken AS h ON e.id = h.empid
        WHERE e.id = 1
        GROUP BY Year

[Fiddle Demo]

希望有人能帮忙谢谢

谢谢，我忘了提到员工每天工作的时间是不同的，所以我使用这个查询来插入假期每天的时间，例如。 jon (empId 1) 周一工作 10 小时，周二工作 6 小时，以此类推。

    $sql= "select  empId,
'".$holidayStart."' as date,
case dayname('".$holidayStart."')
    when 'Sunday' then Sun
    when 'Monday' then Mon
    when 'Tuesday' then Tue
    when 'Wednesday' then Wed
    when 'Thursday' then Thu
    when 'Friday' then Fri
    when 'Saturday' then Sat
else 0 end as hours
from employees where empId = '".$employee."'"  ;
 $result = $mysqli->query($sql);

然后是数据库

id   empid   Mon  Tue Wed Thu Fri Sat Sun
102    1      10   6   4   10  10  0   0

Answer 1

不确定我是否正确解决了问题（我找不到问号:-)）。希望以下查询对您有所帮助：

SET @hoursPerDay := 8;
SET @startdate := DATE('2015-10-05');
SET @enddate   := DATE('2015-10-20');
SET @empid := 1;

SELECT years.*, holidays.*,
    GREATEST(holidays.startdate, years.yearStartDay) AS holidaysStartDay,
    LEAST(holidays.enddate, years.yearEndDay) AS holidaysEndDay
FROM (
    SELECT e.name,
        TIMESTAMPDIFF(YEAR, e.startdate, h.date) AS yearNr,
        DATE_ADD(
            e.startdate, INTERVAL TIMESTAMPDIFF(YEAR, e.startdate, h.date) YEAR
        ) AS yearStartDay,
        DATE_ADD(
            DATE_ADD(e.startdate, 
                INTERVAL TIMESTAMPDIFF(YEAR, e.startdate, h.date) +1 YEAR
            ), INTERVAL -1 DAY
        ) AS yearEndDay,
        e.holidays,
        SUM(h.hours) AS hoursTaken,
        e.holidays * @hoursPerDay - SUM(h.hours) AS hoursLeft
    FROM (
        SELECT empid, DATE, hours
        FROM holidays_taken h 
        -- need union all if didnt have holidays in that year yet
        UNION ALL SELECT @empid AS empid, @startdate AS DATE, 0 AS hours
        UNION ALL SELECT @empid AS empid, @enddate   AS DATE, 0 AS hours
    ) h
    JOIN employees e ON e.id = h.empid
    WHERE h.empid = @empid /* @todo replace with correct employeeID */
    GROUP BY e.id, e.name, e.holidays, yearStartDay, yearEndDay
) years
JOIN (SELECT @startdate AS startdate, @enddate AS enddate) holidays /* @todo replace with $startdate and $enddate */
WHERE holidays.startdate BETWEEN years.yearStartDay AND years.yearEndDay
   OR holidays.enddate   BETWEEN years.yearStartDay AND years.yearEndDay

http://sqlfiddle.com/#!9/10a1d/15

您不需要使用会话变量。只需将它们替换为 PHP 中的值即可。 删除外部选择中您不需要的所有内容。

那么该查询有什么作用： 内部选择与您的查询几乎相同，但

• 可以处理员工年度从 2 月 29 日开始的情况
• UNION ALL 部分创建一个新的一年，如果员工在那一年还没有假期。
• 一年的最后一天不与下一年的第一天重叠。

然后它会查找新定义的假期和所有员工年份之间的交集。然后计算每个员工年度的新假期的日期范围。

要测试更多案例，请将会话变量定义替换为：

-- sample 2: first time taking holidays in a year
SET @startdate := DATE('2017-10-05');
SET @enddate   := DATE('2017-10-20');
SET @empid := 1;


-- sample 3: first year of employee who starts on Feb. 29th
SET @startdate := DATE('2016-10-05');
SET @enddate   := DATE('2016-10-20');
SET @empid := 2;


-- sample 4: second year of employee who starts on Feb. 29th
SET @startdate := DATE('2017-10-05');
SET @enddate   := DATE('2017-10-20');
SET @empid := 2;