PHP：根据键在foreach中分隔值

Question

我正在使用 PHP Laravel。

我需要获取每位员工的总时间/小时数。每个员工都有一个分配的 timeKeeping_empID。 Time_Logs 表有以timeKeeping_empID为外键的Employees的时间日志。

我尝试运行我的代码： 控制器：

function getTotalHours(Request $request)
        {

            $team = Employees::where('managerID', $request->session()->get('employeeID'))->get();
                //I am assigning an array to be grouped according to my employeeID session.
                $teamIDs = array();
                //I am getting my own session so I can see my data as well together with my team
                array_push($teamIDs, $request->session()->get('employeeID'));
                foreach($team as $member) {
                    array_push($teamIDs, $member->employeeID);
                }
                //I am getting the column employeeID which is the same with the teamID
                $empData = Employees::whereIn('employeeID', $teamIDs)->get();
                $timeKeepingIDs = array();
                foreach($empData as $anEmpData) {
                    array_push($timeKeepingIDs, $anEmpData->timeKeeping_empID);
                }
                $timeLogData = Time_Logs::whereIn('timeKeeping_empID', $timeKeepingIDs)->get();

            return view('welcome', compact('timeLogData','request'));
        }

在我看来： $totalHours=0;

        foreach ($timeLogData as $timeLogDatas) {

        $dateToday = new DateTime($timeLogDatas->date);
        $timeFrom = date_create($timeLogDatas->time_in);
        $timeTo = date_create($timeLogDatas->time_out);
        $hoursRendered = date_diff($timeFrom, $timeTo);

        $totalHours=$totalHours += (int) $hoursRendered->format('%h');
        }
        echo "$totalHours";

但结果是所有员工的总小时数。 我需要的是每个员工的总小时数。

这是我的数据库表：

(Employee) 
EmployeeID (primaryKey) 
timeKeeping_empID 
name


(Time_Logs)
id(primaryKey)
timeKeeping_empID
date
time-in
time-out

对不起，我是 PHP 新手。

Answer 1

作为 MVC 模式的原则，您永远不应该将应用程序逻辑放在视图中；将你所有的计算逻辑放在Controller中，然后在你的视图中输出计算值。

话虽如此，您之所以要获取所有员工的时间数据，是因为您将整个员工 ID 号数组传递给了 Timelogdata 的 Where 子句：

$timeLogData = Time_Logs::whereIn('timeKeeping_empID',$timeKeepingIDs)->get();

通过传递员工编号数组，您实际上是在 $timeKeepingIDs 数组中获取所有员工的综合时间日志。

有很多方法可以解决这个问题，但最简单的可能是为每个员工的所有总小时数创建一个关联数组。您必须遍历 $empData 数组中的每个员工，执行计算，并保存一个单独的 $timesheets 数组，如：

//I am getting the column employeeID which is the same with the teamID
$empData = Employees::whereIn('employeeID', $teamIDs)->get();

$timesheets = array();
foreach($empData as $anEmpData) {
    $timeLogData = Time_Logs::whereIn('timeKeeping_empID', $anEmpData->timeKeeping_empID)->get();

    $totalHours = 0;

    $timeLogs = array();
    foreach($timeLogData as &$t) {
        $timeData['dateToday'] = new DateTime($t->date);
        $timeData['timeFrom'] = date_create($t->time_in);
        $timeData['timeTo'] = date_create($t->time_out);
        $timeData['hoursRendered'] = date_diff($timeFrom, $timeTo);
        array_push($timeLogs, $timeData);

        $totalHours=$totalHours += (int) $hoursRendered->format('%h');
    }

    $timesheets[$anEmpData->timeKeeping_empID] = [ 'timeLogs' => $timeLogs, 'totalHours' => $totalHours ];
}

return view('welcome', compact('timesheets','request'));

现在，在您看来，您可以使用@foreach Blade 指令：

<?php
@foreach ($timesheets as $empid => $timesheet)
<p>Timesheet for employee id $empid</p>

    @foreach ($timesheet['timeLogs'] as $timeLog)
        <ul>
        @foreach ($timeLog as $logEntry)

            <li>Date: $logEntry['dateToday']</li>
            <li>Time In: $logEntry['timeFrom']</li>
            <li>Time Out: $logEntry['timeTo']</li>
            <li>Hours rendered: $logEntry['hoursRendered']</li>

        @endforeach
        </ul>
    @endforeach

    Total hours rendered is: $timesheet['totalHours']
@endforeach
?>

我还没有在我的电脑上测试过这个，但我希望你能明白。

希望这会有所帮助！

Answer 2

我认为你应该做的是一个小时数组，而不是把它们加在一起：

    foreach ($timeLogData as $timeLogDatas) {

    $dateToday = new DateTime($timeLogDatas->date);
    $timeFrom = date_create($timeLogDatas->time_in);
    $timeTo = date_create($timeLogDatas->time_out);
    $hoursRendered = date_diff($timeFrom, $timeTo);

    $totalHours[$timeLogDatas->timeKeeping_empID] = $totalHours[$timeLogDatas->timeKeeping_empID] + (int) $hoursRendered->format('%h');
    }
    print_r("$totalHours");

然后您将获得一个包含员工总小时数的数组。 然后你会得到一个像这样的输出：

Array
(
    [123] => 120
    [124] => 95
    [129] => 195
)

其中键是员工 ID，值是他的总小时数。

Answer 3

嘿，我会向你展示 Laravel 魔法：P

function getTotalHours(Request $request)
{
$timeLogData = Time_Logs::groupBy('timeKeeping_empID')->selectRaw('sum(time_out-time_in) as workingHours, timeKeeping_empID')->lists('workingHours','timeKeeping_empID');
}

在你看来

foreach ($timeLogData as $timeLogDatas) {
{{$timeLogDatas->user->name}} - {{$timeLogDatas->workingHours}}
} 

在您的 Time_Logs 模型中，您必须使用此功能

public function user()
    {
        return $this->belongsTo('App\Employee','EmployeeID');
    }

额外：我想你必须在你的 Time_Logs

中使用它

protected $dates = [
        'log_in',
        'log_out',

    ];