如何在 laravel 刀片中使用 foreach 检查 2 个数组之间的匹配？答案

【问题标题】：How to check matches between 2 arrays with foreach in laravel blade?如何在 laravel 刀片中使用 foreach 检查 2 个数组之间的匹配？
【发布时间】：2016-05-19 10:13:37
【问题描述】：

我的数据库中有一组标签。我还附上了当前项目的标签。我想检查标签是否已经附加。这似乎可行，但是当最初附加超过 1 个标签时，我的选择字段中当然会出现重复的项目。我怎样才能避免这种情况？

<select name="tags" multiple required>
    @foreach ($tags as $name)
        @foreach($item->tags as $itemtag)
            @if($name == $itemtag->name)
                <option value="{{$name}}" selected>{{$name}}</option>
            @else
                <option value="{{$name}}">{{$name}}</option>
            @endif
        @endforeach
    @endforeach
</select>

$tags 数组：

 {"9":"Acoustic","3":"Angry","6":"Autumn","10":"Banjo","13":"Bass","14":"Cheerful","12":"Chill","35":"Dirty","8":"Electric","22":"Epiphone","24":"ESP","19":"Fender","33":"Funk","16":"Funny","18":"Gibson","30":"Gretsch","32":"Groovy","1":"Happy","20":"Ibanez","23":"Jackson","31":"Les Paul","28":"Martin","15":"Mellow","21":"Paul Reed Smith","27":"Redwood","2":"Sad","29":"Schecter","17":"Sleepy","34":"Spanish","7":"Spring","4":"Summer","26":"Taylor","11":"Ukulele","5":"Winter","25":"Yamaha"}

$loop->标签数组：

[{"id":1,"created_at":null,"updated_at":null,"name":"Happy","pivot":{"FK_loop_id":2,"FK_tag_id":1}},{"id":4,"created_at":null,"updated_at":null,"name":"Summer","pivot":{"FK_loop_id":2,"FK_tag_id":4}},{"id":14,"created_at":null,"updated_at":null,"name":"Cheerful","pivot":{"FK_loop_id":2,"FK_tag_id":14}},{"id":9,"created_at":null,"updated_at":null,"name":"Acoustic","pivot":{"FK_loop_id":2,"FK_tag_id":9}}]

【问题讨论】：

你能举出两个数组的数据和你目前得到的输出的例子吗？我想这里的问题是您没有可用于查找标签名称的密钥
只是想确认您不想要任何重复记录吗？
没错没错，这其实是更新当前物品标签

标签： php laravel foreach

【解决方案1】：

这应该可行：

<select name="tags" multiple required>
@foreach ($tags as $name)
    @foreach($item->tags as $itemtag)
        @if($name == $itemtag->name)
            <option value="{{$name}}" selected>{{$name}}</option>
            <?php continue 2; ?>
        @endif
    @endforeach
    <option value="{{$name}}">{{$name}}</option>
@endforeach

【讨论】：

这似乎有效！我很想知道这是如何工作的:)

【解决方案2】：

我可能是错的，你的问题仍然有点令人困惑，但我认为下面的代码应该可以做到：

<select name="tags" multiple required>
    @foreach($item->tags as $itemtag)
        @if(in_array($itemtag->name, $tags))
            <option value="{{$name}}" selected>{{$name}}</option>
        @else
            <option value="{{$name}}">{{$name}}</option>
        @endif
    @endforeach
</select>

基本上，您要检查的只是名称属性已经在标签数组中，因此您只需要使用in_array 来检查标签数组是否具有该值

【讨论】：

【解决方案3】：

我认为这是@Sofiene DJEBALI 提供的很好的解决方案
我对此有 1 条建议，使用我的建议，您只需一个 foreach 即可完成此操作
-- 使用 pluck() 函数更新您的查询并仅获取名称；您的查询结果可能看起来像 $itemtag = array(Acoustic, Cheerful, Happy,Summer);
我相信处理时间会更少

<select name="tags" multiple required>
  @foreach($tags as $key => $name)
    <option value="{{$key}}" <?php echo in_array($name, $itemtag)?'selected':'';?>>
     {{$name}}
   </option>
  @endforeach
</select>

【讨论】：