如何在附件php中发送csv文件

Question

我有以下代码

$files = array('/home/my_scripts/my_csvfiles/Multiple_Tracking/Multiple_Tracking_Result_Output_'.$date.'.csv','/home/my_scripts/my_csvfiles/Multiple_Tracking/Multiple_Tracking_Result_Not_match_Output_'.$date.'.csv');

$to = "receiver@mywebsite.com";
$from = "sender@mywebsite.com"; 
$subject ="Multiple Tracking Data Checked Result"; 
$message = "PFA for Multiple Tracking Data Sheet Checked by Script. Date - " . $date ;
$headers = "From: $from";

// boundary 
$semi_rand = md5(time()); 
$mime_boundary = "==Multipart_Boundary_x{$semi_rand}x"; 

// headers for attachment 
$headers .= "\nMIME-Version: 1.0\n" . "Content-Type: multipart/mixed;\n" . " boundary=\"{$mime_boundary}\""; 

// multipart boundary 
$message = "This is a multi-part message in MIME format.\n\n" . "--{$mime_boundary}\n" . "Content-Type: text/plain; charset=\"iso-8859-1\"\n" . "Content-Transfer-Encoding: 7bit\n\n" . $message . "\n\n"; 
$message .= "--{$mime_boundary}\n";

// preparing attachments
for($x=0;$x<count($files);$x++){
    $file = fopen($files[$x],"rb");
    $data = fread($file,filesize($files[$x]));
    fclose($file);
    $data = chunk_split(base64_encode($data));
    $message .= "Content-Type: {\"application/octet-stream\"};\n" . " name=\"$files[$x]\"\n" . 
    "Content-Disposition: attachment;\n" . " filename=\"$files[$x]\"\n" . 
    "Content-Transfer-Encoding: base64\n\n" . $data . "\n\n";
    $message .= "--{$mime_boundary}\n";
}
// send
$ok = @mail($to, $subject, $message, $headers); 
if ($ok) {  echo "Mail sent to $to!";}
else { echo "Mail could not be sent!"; } 

但它会将完整的文件路径作为附件中的文件名发送。 正如我在$files 数组中提到的绝对路径。但是，每当我将相对路径放在数组中时，它都会在电子邮件附件中发送空的 csv 文件。 我只想在附件中发送文件名。那么有什么解决方案我只能在邮件附件中使用正确的数据获取文件名。

Answer 1

获取文件名：

$info = new SplFileInfo($files[$x]);
$fileName = $info->getFilename();

然后穿上：

"Content-Disposition: attachment;\n" . " filename=\"$fileName\"\n" .