【问题标题】:How can I change the order of the box numbers?如何更改箱号的顺序?
【发布时间】:2023-04-02 16:32:01
【问题描述】:
我的盒子里的数字顺序如下:
function boxNumbers(){
let boxes = document.querySelectorAll('.box')
boxes.forEach((box,i)=>{
if(String(i).length==1 || (String(i).length==2 && Number(String(i)[0]))%2==0){
//box.innerHTML = `${100-i}, i=${i}`
box.innerHTML = 100-i
}
else{
box.innerHTML = String(Number(`${9-Number(String(i)[0])}${String(i)[1]}`)+ 1)
}
})
}
如何将其更改为如下所示:
【问题讨论】:
标签:
javascript
arrays
foreach
【解决方案1】:
你可以用这个:
function boxNumbers() {
let boxes = document.querySelectorAll('.box');
let n = Math.sqrt(boxes.length);
[...boxes].reverse().forEach((box, i) => {
box.textContent = i % (n * 2) < n ? i + 1 : i + n - 2*(i % n);
})
}
分配给n 后,它会变得更加通用——仍然假设您的桌子是方形的。通过反转迭代,您消除了对 100- 减法的需要。剩下的是一个公式,它可以检测我们是否在反向序列上,并相应地调整数字。数字“1”将始终位于右下角:
function boxNumbers() {
let boxes = document.querySelectorAll('.box');
let n = Math.sqrt(boxes.length);
[...boxes].reverse().forEach((box, i) => {
box.textContent = i % (n * 2) < n ? i + 1 : i + n - 2*(i % n);
})
}
// Utility to create the table
function fillTable(table, n) {
for (let i = 0; i < n; i++) {
let row = table.insertRow();
for (let j = 0; j < n; j++) {
let cell = row.insertCell();
cell.className = "box";
}
}
}
// Example run with n=5. Adapt as needed
let n = 5
fillTable(document.querySelector('table'), n);
boxNumbers();
table { border-collapse: collapse }
td { border: 1px solid ; width: 20px; height: 20px; text-align: center }
<table></table>
【解决方案2】:
这是一个构建二维数组并将其作为表(行/列)附加到 dom 元素的函数。您可以根据需要将其调整为模板。
适用于任何基数,您的是 5
function buildMatrix(baseNumber){
var flip = false;
var countDownNumber = baseNumber * baseNumber;
var currNumber = countDownNumber;
var matrix = "";
for(i = 0; i < baseNumber; i++) {
if(i !== 0){
currNumber = (flip)? countDownNumber + 1 - baseNumber : countDownNumber;
}
matrix += "<tr>";
for(j = 0; j < baseNumber; j++){
matrix += "<td>" + currNumber + "</td>";
// depending on the direction (flip) we increment or decrement
(flip)? currNumber++ : currNumber--;
countDownNumber--;
}
// change direction at the end of a row
flip = !flip;
matrix += "</tr>";
}
return matrix;
}
var baseSquareNumber = 11; // here you put 5
var matrixHtml = buildMatrix(baseSquareNumber);
document.getElementById("matrix").innerHTML = matrixHtml;
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
</head>
<body>
<table id="matrix">
</table>
</body>
</html>