【发布时间】：2016-08-22 02:20:56
【问题描述】：
我一直在尝试使用光标并按照我在网上找到的教程，我能够想出以下光标。
DELIMITER $$
CREATE PROCEDURE customers_with_oldest_version (INOUT customerCount varchar(4000))
BEGIN
DEClARE customers_with_oldest_version CURSOR FOR
select * from CustomerSoftware where software in (select min(minimumSoftware) from ProductSoftware);
DECLARE CONTINUE HANDLER
FOR NOT FOUND SET @finished = 1;
set @row_entry = "";
open customers_with_oldest_version;
get_customers: LOOP
FETCH customers_with_oldest_version INTO @row_entry;
IF @finished = 1 THEN
LEAVE get_customers;
END IF;
SET @customerCount = @customerCount + 1;
END LOOP;
CLOSE customers_with_oldest_version;
END$$
DELIMITER ;
但是我无法创建这个程序，因为 phpmyadmin 给我一个错误说
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '@row_entry; IF @finished = 1 THEN LEAVE get_customers; END IF; SET @c' at line 16
我在这里错过了什么？
【问题讨论】：
-
你从不使用
@row_entry。你为什么要进去？ -
@Barmar 我打算稍后使用它。我只是想看看是什么导致了这个错误。