请告诉我如何使这段代码更“Pythonic”[关闭]

Question

此代码功能齐全，无需使用错误处理。有没有更有效的方法来写这个？我很想向大家学习。

from getpass import getpass

username = input("Username: ")
grant_access = False

while not grant_access:
  password = getpass("Password: ")
  if password == 'pass123':
    grant_access = True
  elif password != 'pass123':
    while not grant_access:
      password = getpass("Re-enter Password: ")
      if password == 'pass123':
        grant_access = True
      elif password != 'pass123':
        continue

print("Logging in...")

Answer 1

你可以这样做：

from getpass import getpass

username = input("Username: ")
password = getpass("Password: ")

if password != 'pass123':
  while True:
    password = getpass("Re-enter Password: ")
    if password == 'pass123':
      break

print("Logging in...")

甚至像这样：

from getpass import getpass

username = input("Username: ")
password = getpass("Password: ")

while password != 'pass123':
  password = getpass("Re-enter Password: ")

print("Logging in...")