显示每个输出在“X”中显示的次数答案

【问题标题】：Display the number of times each output was displayed in 'X's显示每个输出在“X”中显示的次数
【发布时间】：2020-11-17 16:08:39
【问题描述】：

while True:
    try:
        wins = int(input("enter number of wins: "))                
        draws = int(input("enter number of draws: "))
        losses = int(input("enter number of losses: "))
    except ValueError:
        print('try again')
        continue

    if wins>3:
        print('qualify')
    elif losses>3:
       print('disqualify')
   elif draws>3:
       print('try again')

   restart = str(input('enter "restart" to restart or "quit" to quit'))
   if restart == 'restart':
       continue
   elif restart == 'quit':
       #quit and display number of occurrences of qualify, disqualify and try again in 'X's

【问题讨论】：

这是我第一次使用堆栈溢出，请注意这个烂摊子
请提供预期的minimal, reproducible example。显示中间结果与您的预期不同的地方。我们应该能够复制和粘贴您的代码的连续块，执行该文件，并重现您的问题以及跟踪问题点的输出。这让我们可以根据您的测试数据和所需的输出来测试我们的建议。
您发布的代码挂起等待输入——我们不会为您测试它。您没有显示任何输出，没有错误，没有问题。请从intro tour 重复on topic 和how to ask。

标签： python loops if-statement conditional-statements

【解决方案1】：

首先，您需要跟踪每个结果的计数。您可以使用三个不同的变量来执行此操作，但我认为使用字典会更容易一些，或者更好的是 Counter：

from collections import Counter

counts = Counter()

确保在你的循环之外初始化这个，因为你想在循环的多次迭代中保持相同的计数器；如果你在循环内重置它，它不会跟踪任何东西！

然后跟踪你看到的结果：

    if wins > 3:
        result = "qualify"
    elif losses > 3:
        result = "disqualify"
    elif draws > 3:
        result = "try again"
    else:
        print("Not enough of anything to produce a result!")
        continue
    print(result)
    counts[result] += 1

最后，你可以通过字符串乘法将计数转换为“X”标记：

for result in counts:
    print(f"{result}: {'X' * counts[result]}")

整体看起来像：

from collections import Counter

counts = Counter()
while True:
    try:
        wins = int(input("enter number of wins: "))                
        draws = int(input("enter number of draws: "))
        losses = int(input("enter number of losses: "))
    except ValueError:
        print("try again")
        continue

    if wins > 3:
        result = "qualify"
    elif losses > 3:
        result = "disqualify"
    elif draws > 3:
        result = "try again"
    else:
        print("Not enough of anything to produce a result!")
        continue
    print(result)
    counts[result] += 1

    if str(input('enter "restart" to restart or "quit" to quit')) == "quit":
        break

for result in counts:
    print(f"{result}: {'X' * counts[result]}")

【讨论】：

【解决方案2】：

我不明白你的问题，但根据我的理解，我构建了一个解决方案。这将向您显示合格和不合格的发生结果

qualifycount=0
disqualifycount=0
while True:
    try:
        wins = int(input("enter number of wins: "))                
        draws = int(input("enter number of draws: "))
        losses = int(input("enter number of losses: "))
    except ValueError:
        print('try again')
        continue

    if wins>3:
        print('qualify')
        qualifycount+=1
    elif losses>3:
       print('disqualify')
       disqualifycount+=1
    elif draws>3:
       print('try again')
   
    restart = str(input('enter "restart" to restart or "quit" to quit'))
    if restart == 'restart':
       continue
    elif restart == 'quit':
       #quit and display number of occurrences of qualify, disqualify and try again in 'X's
       print("Number of qualify:"+str(qualifycount))
       print("Number of disqualify:"+str(disqualifycount))
       restart= str(input('press X to run again or press enter to quit'))
       if restart=='X':
           continue
       else:
           break

【讨论】：