如何多次重复代码？在蟒蛇

Question

如何使代码重复，使用户只能猜测随机数的答案 3 次，如何让它停在某个点？谢谢。 这是一个随机数猜谜游戏，我是 python 的初学者，在网上找不到任何可以帮助我的东西（或者可能是我很笨）

import random
print('what difficulty do you want? Type Easy or Hard accordingly')
difficulty = input('')

if difficulty == 'Hard':
    print('your going to have a tough time')
    hardrandomnum = random.randint(1,100)
    def main():
        print('try to guess the number')
        playerguess = float (input(""))
        if playerguess > hardrandomnum: 
            print ("guess a lower number")
        if playerguess < hardrandomnum:
            print("guess a higher number")
        if playerguess == hardrandomnum:
            print("correct") 
        

        restart = 4
        if restart >4:
            main()

        if restart == 4:
            exit()

main()

Answer 1

循环和中断。

例如，如果您想运行代码三次，请将其包装在 for 循环中：

for i in range(3):
   [here goes your code]

或者你可以创建一个while循环并中断：

while(True):
    [here goes your code]
    if condition is met:
        break

Answer 2

你可以使用 for 循环：

for i in range(3):
    #your code 

range()中的数字表示你访问里面的代码的次数 还有while循环，但对于您的用例，for循环应该可以解决问题

Answer 3

使用below answer 提及的循环结构。

while 循环示例

def repeat_user_input(num_tries=3):
    tries = 0
    result = []

    while tries < num_tries:
        tries += 1
        result.append(float(input()))

    return result


print(repeat_user_input())

带有列表理解和range 的示例

def repeat_user_input(num_tries=3):
    return [float(input()) for _ in range(num_tries)]

Answer 4

我相信您正在寻找类似下面的东西？

import random
import sys
guess_counter = 0
random_number = 0
easy_hard = input('Chose your difficulty lever by typing "easy" or "hard" ')
if easy_hard.lower() == 'easy':
    print('Your in luck! You are about to have fun')
    random_number = random.randint(1,10)
elif easy_hard.lower() == 'hard':
    print('Woow this game is not going to be easy')
    random_number = random.randint(1,100)
else:
    print('You need to type either easy or hard and nothing else')
    sys.exit()
while guess_counter < 4:
    user_number = int(input('Guess: ')) 
    if user_number < random_number:
        print('Try higher number')
        guess_counter += 1
    elif user_number > random_number:
        print('Trye lower number')
        guess_counter += 1
    else:
        print('Congrats! You Won')
        break
else:
    print('Ooops! Looks like you luck run out.')