输入 Java 检查整数中的错误

Question

我知道有人问过这个问题，但我尝试应用我在此处看到的内容并收到错误。

package com.company;

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner get_input = new Scanner(System.in);
        System.out.println("Enter your name ");
        String name = get_input.nextLine();


        boolean is_int = false;
        int year_of_birth = 0;
        System.out.println("Enter your year of birth");
        while (!get_input.hasNextInt()) {
        // If the input isn't an int, the loop is supposed to run
        // until an int is input.

            get_input.hasNextInt();
            year_of_birth = get_input.nextInt();
        }
        //year_of_birth = get_input.nextInt();

        System.out.println("Enter the current year");
        int current_year=get_input.nextInt();


        int age = current_year-year_of_birth;


        System.out.println("Your name is " + name + " and you are " + age + " year old.");

        get_input.close();

    }
}

没有循环，一切正常。我的代码有什么问题？为了清楚起见，我试图要求输入，直到输入可以被验证为整数。

非常感谢。

Answer 1

如果您想跳过无效的非整数值，您的循环应如下所示：

    while (!get_input.hasNextInt()) {
        // skip invalid input
        get_input.next();
    }
    // here scanner contains good int value  
    year_of_birth = get_input.nextInt();

Answer 2

如果我理解正确，这对我有用。您需要不断检查扫描仪有什么值，因此您需要在扫描仪中保持前进，而该值不是整数：

        Scanner get_input = new Scanner(System.in);
        System.out.println("Enter your name ");
        String name = get_input.nextLine();

        int year_of_birth = 0;

        System.out.println("Enter your year of birth");
        while (!get_input.hasNextInt()) { //check if it is not integer
            System.out.println("Enter your year of birth"); // ask again
            get_input.next(); //advance through the buffer
        }
        year_of_birth = get_input.nextInt(); //here you get an integer value
        int current_year=get_input.nextInt();
        int age = current_year-year_of_birth;
        System.out.println("Your name is " + name + " and you are " + age + " year old.");

        get_input.close();