井中蜗牛 JavaScript 挑战

Question

这是我关于堆栈溢出的第一个问题，尽管在我没有获得足够的详细信息来理解为什么以这种方式编写代码之前已经回答了这个问题，而且我不只是想在不理解的情况下复制和粘贴解决方案.

蜗牛每天爬 7 英尺，每晚滑回 2 英尺，蜗牛需要多少天才能从给定深度的井中出来？ 示例输入 31 样本输出 6 这是我写的，但是没有用

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
let climb = 0, days = 0;
   for(climb + 7; climb < depth; days++){
       climb += 2;
       console.log(days);
   

Answer 1

试试这个：

  var depth = parseInt(readline(), 10);
  var day = 0;
  for(let climb = 0; climb <= depth;) {
      day +=1;
      climb += 7;
      if(climb >= depth) {
          break;
      }
      climb -= 2;
  }
  console.log(day);

Answer 2

只需输入并写下这个 var day= Math.ceil((depth-2)/5); 并输出！

Answer 3

/* day --> 7++
night --> 2-- */
var day = 0;
var total = 0;
var input = 41;
 while (input>total){
     day++;
     total+=7;
   if (total>=input){
       console.log(day);
       break;
   }
   total = total -2
 }

Answer 4

如 cmets 中所述，无需循环。只需计算出问题的数学并加以利用。

function snailCalc (depth, dailyGain, nightlyLoss) {
  var days = 1;
  var netGain = dailyGain-nightlyLoss;
  if(depth > dailyGain ) {   
    //Basic calc based on net gain taking the first day into account
    days = (depth-dailyGain)/netGain;
    //Add the fist day
    days += 1;
    //We want whole days so use Mathc.ceil
    days = Math.ceil(days)
    //Or we could do all that in one line
    //days = Math.ceil(((depth-dailyGain)/netGain) + 1);
  }
  return days;
}

const gain = 7;
const loss = 2

for(var d = 1; d < 31; d++)
{
  console.log(`Depth: ${d}, Days: ${snailCalc(d, gain, loss)}` )
}

Bob

Answer 5

function main() {
    var depth = parseInt(readLine(), 10);
    console.log(Math.round(depth / 5))
}

Answer 6

您可以更改函数输入并测试snipet：

for more you can run code and check result ↗

例如：main(128) // 26

function main(input) {
  let depth = input

  let climbsUp = 7
  let slipsBack = 2
  let distance = climbsUp - slipsBack
  let days = 0;
  let rDepth = Math.round(depth / distance)

  for (let i = 0; i < rDepth; i++) {
    distance = distance + 5
    days = ++days
    if (days === 6) {
      console.log('days will it take the snail to get out of a well : ' + rDepth)
    } else {
      console.log('days will it take the snail to get out of a well : ' + rDepth)
      break;
    }

  }
}

main(42);
main(128);