python中的高/低游戏答案

【问题标题】：High/low game in pythonpython中的高/低游戏
【发布时间】：2021-08-03 04:07:45
【问题描述】：

'''

import random

correct_num = random.randint(0,10)

guess = int(input('What is your guess?'))
while guess != correct_num:
    if guess > correct_num:
        print('Your guess is to big')
    if guess < correct_num:
        print('Your guess is to small')
    else:
        if guess == correct_num:
            print('Yes! You are correct')

'''

这是我目前所拥有的，当我运行代码时，它会无限打印输出。我怎样才能让它给出一个输出并返回另一个猜测？

【问题讨论】：

以guess = -1开头，这样while循环总是至少运行一次，把guess = int(input(...))放在while循环里面

标签： python loops if-statement while-loop

【解决方案1】：

您可以这样做：

import random

correct_num = random.randint(0,10)


while True:
    guess = int(input('What is your guess?'))
    if guess == correct_num:
        print('Yes! You are correct')
        break
    elif guess > correct_num:
        print('Your guess is to big')
    elif guess < correct_num:
        print('Your guess is to small')

【讨论】：

做if...elif...elif而不是if的3个独立块

【解决方案2】：

您需要在循环内接受输入。另外，您可以设置guess=-1，因为随机数永远不会是-1，因为它不在范围内。

import random
guess=-1
correct_num = random.randint(0,10)
while guess != correct_num:
    guess = int(input('What is your guess?'))
    if guess > correct_num:
        print('Your guess is to big')
    if guess < correct_num:
        print('Your guess is to small')
    else:
        if guess == correct_num:
            print('Yes! You are correct')

【讨论】：

【解决方案3】：

您可以在 if 语句的末尾添加关键字 break，您的问题就解决了。顺便说一句，您也可以尝试让用户说 3 次尝试。在我们的例子中，它只有 1 次尝试。


import random

correct_num = random.randint(0,10)

guess = int(input('What is your guess?'))

while guess != correct_num:

    if guess > correct_num:
        print('Your guess is to big')
        break
    elif guess < correct_num:
        print('Your guess is to small')
        break
    else:
        if guess == correct_num:
            print('Yes! You are correct')
            break

【讨论】：