【发布时间】:2017-03-11 04:33:06
【问题描述】:
我目前正在尝试在菜单按钮单击时实现弹出菜单,如下图所示:
我尝试了 popupwindow 方法,但无法达到确切的情况。 这就是我正在尝试的方式:
private View.OnClickListener showPopupWindow() {
return new View.OnClickListener() {
@Override
public void onClick(View v) {
PopupWindow popUp = popupWindowsort();
popUp.showAsDropDown(v, 1, 1); // show popup like dropdown list
}
};
}
private PopupWindow popupWindowsort() {
// initialize a pop up window type
popupWindow = new PopupWindow(context);
ArrayList<String> sortList = new ArrayList<String>();
sortList.add("VIEW FULL");
sortList.add("REPORT");
sortList.add("ADD TO LIST");
sortList.add("ADD TO CART");
ArrayAdapter<String> adapter = new ArrayAdapter<String>(context, R.layout.drop_down_line,
sortList);
// the drop down list is a list view
ListView listViewSort = new ListView(context);
// set our adapter and pass our pop up window contents
listViewSort.setAdapter(adapter);
// set on item selected
listViewSort.setOnItemClickListener(onItemClickListener());
// some other visual settings for popup window
popupWindow.setFocusable(true);
popupWindow.setWidth(300);
popupWindow.setBackgroundDrawable(getResources().getDrawable(R.drawable.background));
popupWindow.setHeight(WindowManager.LayoutParams.WRAP_CONTENT);
// set the listview as popup content
popupWindow.setContentView(listViewSort);
return popupWindow;
}
private AdapterView.OnItemClickListener onItemClickListener() {
return new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView parent, View view, int position, long id) {
if (position == 0) {
// adapter.notifyDataSetChanged();
} else if (position == 1) {
report_lay.setVisibility(View.VISIBLE);
// adapter.notifyDataSetChanged();
} else {
// adapter.notifyDataSetChanged();
Log.i(TAG, "position2 " + position);
}
dismissPopup();
}
};
}
private void dismissPopup() {
if (popupWindow != null) {
popupWindow.dismiss();
}
}
这也会导致棉花糖出现问题。
如何创建这样的弹出菜单?
【问题讨论】:
标签: android xml android-layout material-design