【问题标题】:Looking for a way to partition date on a monthly basis in Clojure寻找一种在 Clojure 中按月划分日期的方法
【发布时间】:2019-12-20 10:25:09
【问题描述】:

想要将日期范围分成每月的块。

示例输入 - [10/20/2019 - 12/20/2019]

示例输出 - { [10/20/2019 10/31/2019] [11/01/2019 11/30/2019] [12/012019 12/20/2019] }

谢谢

【问题讨论】:

标签: clojure clojure-java-interop


【解决方案1】:

你可以使用java-time:

(refer-clojure :exclude [range iterate format max min])
(use 'java-time)

(->> (iterate plus (local-date 2019 10 20) (days 1))
     (take-while #(before? % (local-date 2019 12 21)))
     (partition-by month)
     (map (fn [dates] [(first dates) (last dates)])))

输出:

([#object[java.time.LocalDate 0x26c16faf "2019-10-20"]
  #object[java.time.LocalDate 0x4113c834 "2019-10-31"]]
 [#object[java.time.LocalDate 0x7d0a5212 "2019-11-01"]
  #object[java.time.LocalDate 0x249fe02f "2019-11-30"]]
 [#object[java.time.LocalDate 0x7345f070 "2019-12-01"]
  #object[java.time.LocalDate 0x26d66577 "2019-12-20"]])

【讨论】:

    【解决方案2】:

    这是您可以做什么的简单草稿(使用 java 互操作,没有外部库):

    首先让我们按月进行迭代,从指定的开始:

    (defn by-month [[mm yyyy]]
      (iterate #(.plusMonths % 1)
               (java.time.YearMonth/of yyyy mm))) 
    
    user> (take 4 (by-month [10 2019]))
    ;;=> (#object[java.time.YearMonth 0x62fc8302 "2019-10"]
    ;;    #object[java.time.YearMonth 0x1a7bc211 "2019-11"]
    ;;    #object[java.time.YearMonth 0x6a466e83 "2019-12"]
    ;;    #object[java.time.YearMonth 0x652ac30f "2020-01"])
    

    然后获取每个 YearMonth 的开始和结束日期:

    (defn start-end [^java.time.YearMonth ym]
      [(.atDay ym 1) (.atEndOfMonth ym)])
    
    ;;=> ([#object[java.time.LocalDate 0xe880abb "2019-10-01"]
    ;;     #object[java.time.LocalDate 0x54aadf50 "2019-10-31"]]
    ;;    [#object[java.time.LocalDate 0x14c1b42d "2019-11-01"]
    ;;     #object[java.time.LocalDate 0x32d0a22c "2019-11-30"]])
    

    现在,按您输入的日期将其包装在一个范围函数中:

    (defn day-range [[mm1 dd1 yyyy1] [mm2 dd2 yyyy2]]
      (let [start (java.time.LocalDate/of yyyy1 mm1 dd1)
            end (java.time.LocalDate/of yyyy2 mm2 dd2)
            internal (->> [mm1 yyyy1]
                          by-month
                          (mapcat start-end)                     
                          (drop 1)
                          (take-while #(neg? (compare % end))))]
        (partition 2 `(~start ~@internal ~end))))
    
    user> (day-range [10 20 2019] [12 20 2019])
    ;;=> ((#object[java.time.LocalDate 0x6a8f92f2 "2019-10-20"]
    ;;     #object[java.time.LocalDate 0x10135df3 "2019-10-31"])
    ;;    (#object[java.time.LocalDate 0x576bcff7 "2019-11-01"]
    ;;     #object[java.time.LocalDate 0x7b5ed908 "2019-11-30"])
    ;;    (#object[java.time.LocalDate 0x6b2117a9 "2019-12-01"]
    ;;     #object[java.time.LocalDate 0x57bf0864 "2019-12-20"]))
    

    现在您可以根据需要对每个起始端对进行后处理:

    (map (fn [[^java.time.LocalDate start ^java.time.LocalDate end]]
           (let [fmt (java.time.format.DateTimeFormatter/ofPattern "MM/dd/yyyy")]
             [(.format start fmt) (.format end fmt)]))
         (day-range [10 20 2019] [12 20 2019]))
    
    ;;=> (["10/20/2019" "10/31/2019"]
    ;;    ["11/01/2019" "11/30/2019"]
    ;;    ["12/01/2019" "12/20/2019"])
    

    另一种方法是按天迭代,然后按[月年]分区,然后依次收集:

    (defn ranges [[mm1 dd1 yyyy1] [mm2 dd2 yyyy2]]
      (let [start (java.time.LocalDate/of yyyy1 mm1 dd1)
            end (java.time.LocalDate/of yyyy2 mm2 dd2)]
        (->> start
             (iterate (fn [^java.time.LocalDate curr] (.plusDays curr 1)))         
             (take-while (fn [^java.time.LocalDate dt] (not (pos? (compare dt end)))))
             (partition-by (fn [^java.time.LocalDate dt] [(.getMonthValue dt) (.getYear dt)]))
             (map (juxt first last)))))
    
    user> (ranges [10 20 2019] [12 20 2019])
    ;;=> ([#object[java.time.LocalDate 0x383f6a9e "2019-10-20"]
    ;;     #object[java.time.LocalDate 0x2ca14c39 "2019-10-31"]]
    ;;    [#object[java.time.LocalDate 0x74d1974 "2019-11-01"]
    ;;     #object[java.time.LocalDate 0x5f6c16cc "2019-11-30"]]
    ;;    [#object[java.time.LocalDate 0x74f63a42 "2019-12-01"]
    ;;     #object[java.time.LocalDate 0x4b90c388 "2019-12-20"]])
    

    它会产生一些不需要的中间值,但也给你一种方法来分割你想要的范围。

    【讨论】:

      【解决方案3】:

      直接的 Java 互操作是这里的方法:

        (let [start-ld  (LocalDate/parse "2019-10-20")
              start-bom (.with start-ld (TemporalAdjusters/firstDayOfMonth))
              start-eom (.with start-ld (TemporalAdjusters/lastDayOfMonth))]
      
      start-bom => #object[java.time.LocalDate 0x1a69aaa8 "2019-10-01"]
      start-eom => #object[java.time.LocalDate 0x329970b5 "2019-10-31"]
      

      您可以像这样增加月份:

              next-bom  (.plusMonths start-bom 1)
      

      得到

      next-bom => #object[java.time.LocalDate 0x21ced418 "2019-11-01"]
      

      然后你可以写一个循环。

      【讨论】:

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