SQL FUNCTION LIKE SEARCH ISSUE

Question

请帮忙修复我的sql函数！

在我的 sql 函数中，我有一个临时表

参数传递给函数@searchstring ---- "'%carrots%' AND tmp.ItemDescription like '%baby%'"

Declare  @tempvalues table  (itemdescription nvarchar(max))

@tempvalues  VALUES

-----------------------

CARROTS, BABY, CLASS I, FRESH
CARROTS, BABY, FROZEN
CARROTS, CLASS I, FRESH

------------------

所以在函数 iam 中传递值以使用类似查询搜索数据，如果匹配，我需要在另一个表中插入数据 喜欢

在下面的 temptable 中如果匹配我需要插入 1 作为对应的行

Declare  @tempfinal table  (itemdescription nvarchar(max),matchcontains int)

**insert into @tempfinal select ItemDescription,'1'as matchcontains  from  @tempvalues tmp where tmp.ItemDescription like @searchstring**  

但@tempfinal 中没有插入任何内容

我需要搜索所有匹配的单词

请帮忙寻找解决办法

示例函数

CREATE FUNCTION dbo.UDF_PredictItems_testfreetextdemo  
(  
 @FTSExpression    NVARCHAR(4000) 
)
RETURNS @Result TABLE   
(

  itemdescription  NVARCHAR(4000),
  matchcontains int

)  
AS  
BEGIN           
 Declare  @tempvalues table  (itemdescription nvarchar(max))                    
 insert into @tempvalues values ('CARROTS, BABY, CLASS I, FRESH') ,
 ('CARROTS, BABY, FROZEN 2.5 KGS') ,
 ('CAKE, CARROT, FROZEN 1 KGS') ,
 ('CARROTS, CLASS I, FRESH')  


 declare @containExpression nvarchar(max)
 set @containExpression =replace(replace(replace(@FTSExpression,' ','<>'),'><',''),'<>',' ') 
 set @containExpression=(Select  replace(@FTSExpression, ' ', '%'))   
 set @containExpression=(Select  replace(@containExpression, ' ', ' AND tmp.ItemDescription like ')) 
 set @containExpression=(select '''%'+@containExpression+'%''')  




  declare @tempfinal table(ItemDescription nvarchar(max),matchcontains int)      
  insert into @tempfinal select ItemDescription,CAST('1' AS INT) as matchcontains  from  @tempvalues tmp where tmp.ItemDescription like @containExpression    

   insert into @Result ( itemdescription,matchcontains )           
   select  itemdescription,0 from @tempfinal

   return;
   END

调用函数

SELECT * from UDF_PredictItems_testfreetextdemo('Carrots baby')

Answer 1

我已经检查了你所描述的 LIKE 运算符，这对我来说很好。

Declare  @tempvalues table  (itemdescription nvarchar(max))

INSERT INTO @tempvalues  
VALUES ('CARROTS'), ('BABY'), ('CLASS I'), ('FRESH'),('CARROTSI'), ('BABYI'), ('FROZENI'), ('CARROTSI'), ('CLASS I'), ('FRESH')

DECLARE @searchstring NVARCHAR(50) = '%carrots%'
SELECT * FROM @tempvalues WHERE itemdescription LIKE @searchstring

输出：

胡萝卜

胡萝卜

胡萝卜

查看我的结果here

更新

所以问题不在LIKE 运算符中，作为@Antonios Katopodis 的答案，您应该插入int 而不是varchar 类型

修复后更新

你的问题在这里

set @containExpression=(select '''%'+@containExpression+'%''')

你应该这样修复

set @containExpression=(select '%'+@containExpression+'%')  

Answer 2

您的查询是

INSERT INTO @tempfinal
SELECT 
   ItemDescription,
  '1' as matchcontains
FROM @tempvalues tmp
WHERE tmp.ItemDescription like @searchstring**

问题在于您尝试将 char 插入 int 字段。 所以试试这个：

INSERT INTO @tempfinal
SELECT 
   ItemDescription,
  CAST('1' AS INT) as matchcontains
FROM @tempvalues tmp
WHERE tmp.ItemDescription like @searchstring**

或者

INSERT INTO @tempfinal
SELECT 
   ItemDescription,
  1 as matchcontains
FROM @tempvalues tmp
WHERE tmp.ItemDescription like @searchstring**