【发布时间】:2017-09-21 18:47:23
【问题描述】:
我尝试从 link 加载和解析 JSON 文件
但我有JSON_ERROR_SYNTAX 的问题和为foreach() 提供的无效参数。为什么会这样?
[{ "Manufacturer": "Toyota", "Sold": 1200, "Month": "2012-11" }, { "Manufacturer": "Ford", "Sold": 1100, "Month": "2012-11" }, { "Manufacturer": "BMW", "Sold": 900, "Month": "2012-11" }, { "Manufacturer": "Benz", "Sold": 600, "Month": "2012-11" }, { "Manufacturer": "GMC", "Sold": 500, "Month": "2012-11" }, { "Manufacturer": "HUMMER", "Sold": 120, "Month": "2012-11" }]
<?php
$url = "http://www.pureexample.com/backend/data/car-sale.json";
$url = file_get_contents($url);
print_r($url);
$url = stripslashes($url);
print_r($url);
$url = str_replace("\n", "", $url);
print_r($url);
$url = iconv('UTF-8', 'UTF-8//IGNORE', utf8_encode($url));
print_r($url);
$url = json_decode($url, true);
// Add this switch to your code
switch (json_last_error())
{
case JSON_ERROR_NONE:
echo ' - No errors';
break;
case JSON_ERROR_DEPTH:
echo ' - Maximum stack depth exceeded';
break;
case JSON_ERROR_STATE_MISMATCH:
echo ' - Underflow or the modes mismatch';
break;
case JSON_ERROR_CTRL_CHAR:
echo ' - Unexpected control character found';
break;
case JSON_ERROR_SYNTAX:
echo ' - Syntax error, malformed JSON';
break;
case JSON_ERROR_UTF8:
echo ' - Malformed UTF-8 characters, possibly incorrectly encoded';
break;
default:
echo ' - Unknown error';
break;
}
foreach($koyim as $data){
echo $data['Manufacturer'];
echo $data['Sold'];
echo $data['Month'];
echo "<br/>";
}
?>
【问题讨论】:
-
为什么在
json_decode()之前使用stripslashes()、str_replace()、iconv()和utf8_encode()? -
网址(在您的转换之前)是有效的 json。你现在知道该去哪里看 :)
-
如果你的 apache 服务器只服务一个网站,使用 json_last_error() 可能是有用的,但是如果你从其他网站生成的其他错误中得到错误,这个函数会触发最后一个错误最后一次调用函数 json_encode 或 json_decode。
-
json 在所有地方都无效!