使用 fopen 写入 2 个文件

Question

我正在使用下面的脚本加入多个 CSV 文件并写入一个文件。

如何编写相同的内容并创建两个不同文件名的不同文件？

/////////// ---- JOINING THE FILES ---- ///////////

$nn = 0;
foreach (glob("*.csv") as $filename) {

if (($handle = fopen($filename, "r")) !== FALSE) {

    while (($data = fgetcsv($handle, 0, ",")) !== FALSE) {
        $c = count($data);
        //$csvarray[$nn][] = $filename;
        for ($x=0;$x<$c;$x++)
        {
            $csvarray[$nn][] = $data[$x];
        }
        $nn++;
    }

    fclose($handle);
}

}

$fp = fopen("../newfile.csv", "w");//output file set here

foreach ($csvarray as $fields) {
fputcsv($fp, $fields);
}

// Need to create another file with the same contents here!!

fclose($fp);

Answer 1

$fp1 = fopen("../newfile1.csv", "w");//output file set here
$fp2 = fopen("../newfile2.csv", "w");//output file set here

foreach ($csvarray as $fields) {
    fputcsv($fp1, $fields);
    fputcsv($fp2, $fields);
}

Answer 2

我意识到我可以做到这一点..在这条线之后..

// Need to create another file with the same contents here!!

$fq = fopen("../another_new_file.csv", "w"); 

foreach ($csvarray as $fields) {
   fputcsv($fq, $fields);
}