如何通过按钮从列表中传递变量[关闭]

Question

我的目标是读取目录，将项目添加到列表中，添加单个按钮以删除文件，然后添加代码以删除所选文件。删除不是问题，但传递文件是。

这是我尝试过的：

<?php

 if ($handle = opendir('userStorage/Storage1')) {
   while (false !== ($file = readdir($handle)))
      {
          if ($file != "." && $file != "..")
      {
            $filelocation = "userStorage/Storage1/$file";
            $thelist .= '<p1>'.$file.'</p1><form method="post">
            <button>Download</button>
            <button type="submit" name="delete'.$file.'" value="Submit" >Delete</button><br></form>';
          }
       }
  closedir($handle);
  }       
?>

<?php
if($_POST["delete'.$file.'"] == "Submit" ) {
    
        echo "File to be deleted: $file";
    }
  ?>

Answer 1

试试这个

<?php

if (isset($_POST['delete'])) {
    unlink(__DIR__ . DIRECTORY_SEPARATOR . $_POST['file']);
}

if (isset($_POST['download'])) {
    header('Location: ' . $_POST['file']);
}

$files = array_diff(scandir(__DIR__), ['..', '.']);

foreach ($files as $file) {
    echo "
        <p>{$file}</p>
        <form action='' method='POST'>
            <input type='hidden' name='file' value='{$file}'>
            <input type='submit' name='download' value='Download'>
            <input type='submit' name='delete' value='Delete'>
        </form>
    ";
}