一个接一个地打印文件的句子

Question

我有一个包含 4 个段落的文本文件 (input.txt)，我必须将这些段落的句子一个接一个地写在另一个文件 (output.txt) 中（用换行符分隔）。

原文件中的句子用'.'、'!'分隔和'?'。

我已经完成了，但我的代码有问题。 output.txt文件中有些句子没有换行

我的代码：

while(1) {
    c = fgetc(fp);
    if( feof(fp) ) {
      break;
    }

    c_next = fgetc(fp);

    if( feof(fp) ) {
      fprintf(fp_output, "%c", c);
      break;
    } else {
      if( c=='.' || c=='?' || c=='!' ) {
        fprintf(fp_output, "%c\n", c);
      } else {
        if( c=='\n' ) {
          fprintf(fp_output, "%c", c_next);
        } else if( c_next=='\n' ) {
          fprintf(fp_output, "%c ", c);
        } else {
          fprintf(fp_output, "%c%c", c, c_next);
        }

      }
    }

  }

例如，对于输入文件：

This is the first sentence. The second one contains some more words, other words,
more words, etc. The third sentence has; and more like: this, that, those.

This is the second paragraph. And now a question? Only an exclamative
sentence is missing!

This is the third paragraph. Another component - word - would be this.
The final sentence of the paragraph!

This is the last paragraph.

我的代码得到以下输出：

This is the first sentence.
The second one contains some more words, other words, more words, etc. The third sentence has; and more like: this, that, those.
This is the second paragraph.
And now a question?
Only an exclamative sentence is missing!
This is the third paragraph. Another component - word - would be this.The final sentence of the paragraph!
This is the last paragraph.

问题出在第二行和第六行。每行最多1句。

欢迎任何想法、提示或解决方案。

谢谢

Answer 1

以下代码：

1. 仅经过轻微测试
2. 干净编译
3. 忽略多个句尾标记，即使由空格分隔
4. 忽略换行序列
5. 忽略句子前的空格

现在，代码

#include <stdio.h>  // fopen(), fclose(), fgetc(), putchar()
#include <ctype.h>  // isalpha()
#include <stdlib.h> // exit(), EXIT_FAILURE

#define PERIOD (',')
#define QUESTION_MARK ('?')
#define EXCLAMATION_MARK ('!')

int main( int argc, char *argv[] )
{
    if( 2 > argc )
    {
        fprintf( stderr, "USAGE: %s <inputFileName>\n", argv[0] );
        exit( EXIT_FAILURE );
    }

    // implied else, command line parameter exists

    FILE *fp = NULL;
    if( NULL == (fp = fopen( argv[1], "r" ) ) )
    {
        perror( "fopen failed" );
        exit( EXIT_FAILURE );
    }

    // implied else, fopen successful

    int inSentence = 0;
    int ch;
    while( EOF != (ch = fgetc( fp ) ) )
    {
        if( inSentence )
        {
            putchar( ch );
            if( PERIOD == ch || EXCLAMATION_MARK == ch || QUESTION_MARK == ch)
            {
                inSentence = 0;
                putchar( '\n' );
            }
        }

        else // if( !inSentence )
        {
            if( isalpha( ch ) )
            { // then not white space nor more punctuation
                inSentence = 1;
                putchar( ch );
            }
        }
    } // end while

    // cleanup
    if( inSentence )
    {
        putchar( '\n' );
    }

    fclose( fp );
} // end function: main

Answer 2

您的代码每次读取 2 个字符，但只检查第一个字符。所以如果 c_next 是 ".!?"，它就会失败。

已更新。参见“if(c=='\n')”部分。我还不能发表评论。

#include <stdio.h>

int main(){

FILE* fp, *fo;
int c, flag = -1;
fp = fopen("input.txt", "r");
fo = fopen("output.txt", "w");
while(fp != NULL){
  c = fgetc(fp);
  if(feof(fp)) break;

  if(c=='\n'){
    fprintf(fo, " ");
    continue;
  }

  if(flag != '.' && flag != '!' && flag != '?'){
    fprintf(fo, "%c", c);
  }
  else{
    fprintf(fo, "\n");
    if(c != ' '){
      fprintf(fo, "%c", c);
    }
  }
  flag = c;
}
fclose(fp);
fclose(fo);

return 0;
}