多个 URL 保存 json 数据

Question

我正在尝试一次调用多个（超过 10 个 url）并保存所有这 10 个 url 的数据，这些数据将以 json 格式保存并尝试保存在我的位置

这是我尝试过的以下代码，使用它我只能获取保存在我的 json 文件中的最后一个 URL 的数据。如何获取所有 URL 的数据并存储在单个 json 文件中？

import json
import requests

URLs = ['http://httpbin.org/ip',
'http://httpbin.org/user-agent',
'http://httpbin.org/headers']

json_list = []
for url in URLs:
    data = requests.get(url)
    resolvedwo = data.json()
    with open('resolvedworesolution.json', 'w') as f:
         json.dump(resolvedwo, f)

Answer 1

您的问题是您每次都在循环中覆盖文件。相反，将循环结果存储在一个列表中并仅将其写入文件一次

import requests
import json

URLs = ['http://httpbin.org/ip',
        'http://httpbin.org/user-agent',
        'http://httpbin.org/headers']

json_list = []

for url in URLs:
    data = requests.get(url)
    resolvedwo = data.json()
    json_list.append(resolvedwo)

with open('resolvedworesolution.json', 'w+') as f:
    json.dump(json_list, f, sort_keys=True, indent=4)

输出：

[
    {
        "origin": "137.221.143.66, 137.221.143.66"
    },
    {
        "user-agent": "python-requests/2.21.0"
    },
    {
        "headers": {
            "Accept": "*/*",
            "Accept-Encoding": "gzip, deflate",
            "Host": "httpbin.org",
            "User-Agent": "python-requests/2.21.0"
        }
    }
]

Answer 2

写入文件时，以w 模式打开文件将在写入之前擦除/截断内容。

with open('resolvedworesolution.json', 'a') as f:

应该可以解决你的问题

Answer 3

在写入文件时使用append mode 以“保留”现有数据：

import json
import requests
URLs = ['http://httpbin.org/ip',
'http://httpbin.org/user-agent',
'http://httpbin.org/headers']

json_list = []
for url in URLs:
    data = requests.get(url)
    resolvedwo = data.json()
    with open('resolvedworesolution.json', 'a') as f:   # Using the append mode
        json.dump(resolvedwo, f)
        f.write("\n")                                   # new line for readability

输出：

{"origin": "159.122.207.241, 159.122.207.241"}
{"user-agent": "python-requests/2.21.0"}
{"headers": {"Accept": "*/*", "Accept-Encoding": "gzip, deflate", "Host": "httpbin.org", "User-Agent": "python-requests/2.21.0"}}

编辑：

您可以一次性将响应写入文件：

with open('resolvedworesolution.json', 'a') as f:
    f.write(str(resolvedwo))
    f.write("\n")

或

for url in URLs:
    data = requests.get(url)
    with open('resolvedworesolution.json', 'a') as f:
        f.write(data.text)
        f.write("\n")

Answer 4

您可以将信息存储在可以整体序列化的对象中：

import json
import requests

URLs = ['http://httpbin.org/ip',
'http://httpbin.org/user-agent',
'http://httpbin.org/headers']

json_list = []
for url in URLs:
    data = requests.get(url)
    resolvedwo = data.json()
    json_list.append(resolvedwo)

with open('resolvedworesolution.json', 'w+') as f:
    json.dump(json_list, f)

Answer 5

代替：

resolvedwo = data.json()

你可能想要：

resolvedwo += data.json()