你如何在java中更改构造函数的对象的参数？ [关闭]

Question

我正在积极学习，所以请耐心等待，例如，假设我有一个包含点数和名称的玩家的构造函数（没有参数）。当我去一个不同的类时，我从这个构造函数中创建一个对象，在游戏的后期，我将如何将诸如分数之类的参数从 0 更改为，我不知道是 100。我会怎么做。我尝试在谷歌搜索，但没有人给出答案。

Answer 1

用户.java

public class User {

    private String name;
    private int points;

    public User() {
        this.name = name;
        this.points = points;
    }

    //Getting of value points
    public int getPoints() {
        return points;
    }

    //Setting of value points
    public void setPoints(int points) {
        this.points = points;
    }

}

OtherClass.java

public class OtherClass() {
    User user = new User(); //Calling of constructor
    user.setPoints(100); //function setPoints being called; setting value to 100
    System.out.println(user.getPoints());
}

Answer 2

首先你要了解java中Encapsulation的概念。这里将一个类的variables 声明为private 和public setter 和getter 提供了修改和查看变量值的方法。 请点击以下链接以供进一步参考：

• Tutorials Point
• How do getters and setters work?

播放器类：

public class Player {

    private String name;
    private int score;

    public Player() {
    }

    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }

    public int getScore() {
        return score;
    }
    public void setScore(int score) {
        this.score = score;
    }

    @Override
    public String toString() {
        return "Player [name=" + name + ", score=" + score + "]";
    }
}

测试类：

public class TestPlayer {
    public static void main(String[] args) {
        Player player = new Player();
        player.setName("Omar Hossain");
        // set score 100
        player.setScore(100);

        System.out.println(player);

        // increment score by 10
        player.setScore(player.getScore() + 10);
        System.out.println("Updated score of player: " + player.getScore());
    }
}