为什么我没有得到正则表达式组值

Question

从这个帖子回答得到了一些很大的帮助here

现在我正在尝试在我的多行字符串中捕获几个模式，但无法正常工作。有什么提示吗？

这是一个 .net fiddle 我正在玩

    desired result:
    //these can be letters
      
    1: 3333  
    2: 1111 

代码：

using System;
using System.Text.RegularExpressions;

public class Program
{
    public static void Main()
    {
        var item = " john smith (ABCDEFG) <js@email.com>\n" + 
            "target1 = 3333, j\n" + 
            "target2 1111, ";
        String[] patternArr = {"(?:\\s*)", 
                               "(?<target1>target1 = (\\w+)])", // capture the first target
                                "(?:\\s*)", 
                               "(?<target2>target2 (\\w+))", // captures the second target
 };
        var pattern = String.Join("", patternArr);
        var m = Regex.Match(item, pattern);
        if (m.Success)
        {
            Console.WriteLine("target1: {0}", m.Groups["target1"]);
            Console.WriteLine("target2: {0}", m.Groups["target2"]);
        }
    }
}

Answer 1

你可以使用

var pattern = @"target1 = (?<target1>\w+).*\ntarget2\s+(?<target2>\w+)";

请参阅regex demo。 正则表达式详细信息：

• target1 = - 文字字符串
• (?<target1>\w+) - 组“target1”：一个或多个单词字符
• .* - 该行的其余部分
• \n - 换行符
• target2 - 文字字符串
• \s+ - 一个或多个空格
• (?<target2>\w+) - 组“target2”：一个或多个单词字符

见C# demo：

using System;
using System.Text.RegularExpressions;
 
public class Program
{
    public static void Main()
    {
        var item = " john smith (ABCDEFG) <js@email.com>\n" + 
            "target1 = 3333, j\n" + 
            "target2 1111, ";
        var pattern = @"target1 = (?<target1>\w+).*\ntarget2\s+(?<target2>\w+)";
        var m = Regex.Match(item, pattern);
        if (m.Success)
        {
            Console.WriteLine("target1: {0}", m.Groups["target1"]);
            Console.WriteLine("target2: {0}", m.Groups["target2"]);
        }
    }
}

输出：

target1: 3333
target2: 1111