Python 3 嵌套的 While 循环

Question

我创建了一个函数来要求用户输入一天的工作小时数，整个事情都会返回，除了如果输入的值不正确，如果输入的值是，它不会显示错误消息小于 0 大于 24 它只是再次要求输入。

def hours_for_days(week_no,day):
  i = -1
  input_string = "Enter number of hours for week " + str(week_no) + " " + day + ": "
  while i <0
    work_time = rawinput(input_string)
    try:
      i = int(work_time)
    except ValueError:
      print("Enter a number: ")
    else:
      while 24 < i
        work_time = rawinput(input_string)
      try:
        i = int(work_time)
      except ValueError:
        print("Enter a number: ")
      else:
        if i < 0
          print("Enter a number between 0 and 24")
        if i > 24
          print("Enter a number between 0 and 24")

Answer 1

您可以添加：

while 1:   
    work_time = rawinput(input_string)
    try:
        i = int(work_time)
        if not (0 <= i <= 24):
            raise(IndexError)
        break
    except ValueError:
        print("Enter a number: ")
    except IndexError:
        print("Number must be between 0 and 24")