如何在正则表达式匹配后使用正则表达式删除特定文本部分

Question

（不，Python regex, how to delete all matches from a string 不能解决我的问题）

假设我有这个列表：

names = ['your name', 'the name', 'his name', 'her name', 'their name', 'employer name', "employer's name", "father's name",
        "mother's name", "maiden name", "son's name", "daughter's name", "brother's name", "sister's name"]

假设我有这段文字：

text = "What is your name?  Well,  uh it's John Smith.  Thanks for asking. Anyway, I'd doing well."

如何使用正则表达式在文本中查找列表名称的每个元素，并将元素之后的文本块（例如，长度为 50）替换为“[name]”。所以我的输出是：

text = "What is your name [name] Anyway, I'd doing well."

到目前为止，我在下面有这段代码，但它只用“[name]”替换元素，而不是元素后面的实际文本。

def my_replace3(match):
    match = match.group()
    return " [name] "

def no_name(text):
    names = ['your name', 'the name', 'his name', 'her name', 'their name', 'employer name', "employer's name", "father's name",
        "mother's name", "maiden name", "son's name", "daughter's name", "brother's name", "sister's name"]
    regex = re.compile(r'\b(' + '|'.join(names) + r')\b', re.IGNORECASE)
    text = re.sub(regex, my_replace3, text)
    return text

我不是一个出色的正则表达式专家，因此非常感谢您的帮助。

Answer 1

如果要在匹配后替换 50 个字符，请在正则表达式中添加 .{50}。

然后在替换字符串中使用反向引用将匹配的字符串复制到替换。

def no_name(text):
    names = ['your name', 'the name', 'his name', 'her name', 'their name', 'employer name', "employer's name", "father's name",
        "mother's name", "maiden name", "son's name", "daughter's name", "brother's name", "sister's name"]
    regex = re.compile(r'\b(' + '|'.join(map(re.escape, names)) + r')\b.{50}', re.IGNORECASE)
    text = re.sub(regex, r'\1 [name]', text)
    return text

在将应该完全匹配的字符串插入到正则表达式中时，您还应该使用re.escape()，以防其中任何一个包含正则表达式运算符。